-1

到目前为止,我在当前目录中创建了一个名为“src”的文件夹

new File("src").mkdir();

然后如果 src 文件夹中有任何 .java 文件,我想将它们存储在数组中

JavaFileObject javaFileObjects[] = new JavaFileObject[]{};

有人可以提供一个解决方案,用 src 文件夹中的 .java 文件填充这个数组。

4

2 回答 2

1

是的,正如评论所说,使用 aFileFilter并检查.java扩展名。

于 2013-03-30T18:32:10.933 回答
0

像这样:

File parentDirectory = new File("src");
File [] javaFiles = parentDirectory.listFiles(new RecursiveExtensionFileFilter(".java"));

这是一个您可能会发现有用的过滤器类:

package util;

import org.apache.commons.lang3.StringUtils;

import java.io.File;
import java.io.FileFilter;

/**
 * RecursiveExtensionFileFilter for filtering only Word .doc files
 * @author Michael
 * @link
 * @since 2/13/13 10:21 AM
 */
public class RecursiveExtensionFileFilter implements FileFilter {
    public static final String DEFAULT_WORD_EXTENSION = ".doc";
    private final String extension;
    private final boolean makeLowerCase;

    public RecursiveExtensionFileFilter(String extension) {
        this(extension, false);
    }

    public RecursiveExtensionFileFilter(String extension, boolean makeLowerCase) {
        if (StringUtils.isBlank(extension))
            throw new IllegalArgumentException("file extension cannot be blank or null");
        this.extension = extension;
        this.makeLowerCase = makeLowerCase;
    }

    @Override
    public boolean accept(File pathname) {
        boolean isWordDocOrDirectory = false;
        if (pathname != null) {
            if (pathname.isDirectory()) {
                isWordDocOrDirectory = true;
            } else {
                String absolutePath = pathname.getAbsolutePath();
                if (this.makeLowerCase) {
                    absolutePath = absolutePath.toLowerCase();
                }
                isWordDocOrDirectory = (absolutePath.lastIndexOf(this.extension) == (absolutePath.length() - this.extension.length()));
            }
        }
        return isWordDocOrDirectory;
    }
}
于 2013-03-30T18:34:13.423 回答