0

我有一个如下所示的关联数组:

Array (
    [0] => Array (
        [amount] => 3
        [name] => Chuck
    )
    [1] => Array (
        [amount] => 2
        [name] => Steve
    )
    [2] => Array (
        [amount] => 5
        [name] =>
    )
    [3] => Array (
        [amount] => 4
        [name] => Chuck
    )
    [4] => Array (
        [amount] =>
        [name] => Chuck
    )
)

我需要删除缺少名称或数量的值,例如 [2] 和 [4],然后将每个名称的总数相加,以便最终数组为:

Array (
    [0] => Array (
        [amount] => 7
        [name] => Chuck
    )
    [1] => Array (
        [amount] => 2
        [name] => Steve
    )
) 
4

2 回答 2

2

对于现在正在寻找这个的人来说,这会更干净:

$sum = array_sum(array_column($data, 'amount'));
于 2020-09-08T09:36:02.780 回答
0

试试这个:

$starting_array = array( ... ); // Initial array with your setup
$final_array = array();
$sum = 0;

foreach ($starting_array as $idx => $data) {
  if (!empty($data['amount']) && !empty($data['name'])) {
    $final_array[$idx] = $data;
    $sum += $data['amount'];
  }
}

// After looping through all of the items, $final_array should contain all
// of the specific items that have an amount and name set. In addition, the
// total of all of the amounts will be in $sum.

看看 php 的empty(). 注意:如果0是一个允许的值,您可能想is_null()改用。

于 2013-03-30T02:37:05.020 回答