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我在编写一个 OAM 程序时遇到问题,该程序会生成一个以 1 开头的交替符号的奇数序列。

我写了一个程序,但它不起作用,我不知道为什么。因为这是一种罕见的语言,如果有人可以帮助并解释我做错了什么,那就太好了。

X,NOOP
Y,NOOP 
LDA stdin
loop, SET 1
LDA Y
STA 0
LDA X
DEC
STA X #X = X - 1
LDA X #ACC = X
4

1 回答 1

0

其他读者想知道这到底是怎么回事:
一个名为的基于 Web 的One Address Machine编译器/汇编器/仿真器OAMulator在这里

你要求一个OAM program that generates a sequence of odd numbers with alternating signs starting with 1(没有指定最大值)。
我会解释你想要以下输出:1, -3, 5, -7, 9, -11, 13, -15 etc....

我假设你LDA stdin的意思是要求最大值,但你似乎没有将它存储在STA. 此外,BR在初始化变量xy. 我也真的不明白你的代码将如何交替符号......

我先写OAMPL代码作弊:

n = 1                       #Init number n as 1
PRINT "enter max number:"   #Ask for max number
READ i                      #Read that number from input, storing it as i
LOOP (/ i 2)                #Calculate number of iterations, passing that to LOOP
  IF t                      #If t (toggle)
    t = 0                   #Toggle falsy
    PRINT (- 0 n)           #Print 0-counter
  ELSE
    t = 1                   #Toggle truthy
    PRINT n                 #Print counter
  ENDIF
  n = (+ n 2)               #Increase counter by 2
END
EXIT                        #Exit program

这将编译为以下内容OAM Assembly

# Emitted by the OAMPL compiler
1.  BR  5   # branch to program block
# Variable storage allocation block
2. n,   NOOP    # variable n
3. i,   NOOP    # variable i
4. t,   NOOP    # variable t
# Begin OAM program block
# OAMPL: n = 1
5.  SET 1
6.  STA n
# OAMPL: PRINT "enter max number:"
7.  SET "enter max number:"
8.  STA stdout
# OAMPL: READ i
9.  LDA stdin
10. STA i
# OAMPL: LOOP (/ i 2)
11. SET 2
12. STA 14
13. BR 15
14. NOOP    # intermediate value
15. LDA i
16. DIV 14
17. BR L18
18. NOOP    # loop counter
# OAMPL: IF t
19. LDA t
20. BRZ I20
# OAMPL: t = 0
21. SET 0
22. STA t
# OAMPL: PRINT (- 0 n)
23. LDA n
24. STA 26
25. BR 27
26. NOOP    # intermediate value
27. SET 0
28. SUB 26
29. STA stdout
# OAMPL: ELSE
30. BR I30
31. I20,    NOOP
# OAMPL: t = 1
32. SET 1
33. STA t
# OAMPL: PRINT n
34. LDA n
35. STA stdout
# OAMPL: ENDIF
36. I30,    NOOP
# OAMPL: n = (+ n 2)
37. SET 2
38. STA 40
39. BR 41
40. NOOP    # intermediate value
41. LDA n
42. ADD 40
43. STA n
# OAMPL: END
44. LDA 18
45. DEC
46. L18,    STA 18
47. BRP 19
# OAMPL: EXIT
48. HLT

注意:您也可以省略注释 ( # comment) 和前导 (line-) 编号。

如果我输入50-input字段(回答最大值问题)并点击execute(编译后!),我得到以下output结果:

enter max number:
1
-3
5
-7
9
-11
13
-15
17
-19
21
-23
25
-27
29

希望这可以帮助!

于 2013-07-12T07:21:21.610 回答