2

我目前正在用python制作一个球击中一组盒子的游戏。我已经加载了一张草的图像,我想让盒子站在上面,草图像是 600 x 151 像素。到目前为止,我所有的盒子和球都完美地出现了,但目前不起作用的是当我尝试加载图像并显示它以便盒子可以站在草地图像上而不是掉落时。

import pygame
from pygame.locals import *
from pygame.color import *
import pymunk as pm
from pymunk import Vec2d
import sys
from random import randint

def to_pygame(p):
    """Small hack to convert pymunk to pygame coordinates"""
    return int(p[0]), int(-p[1]+600)


def add_box(space, size, pos, mass=1.0):
    # pos is a Vec2d object
    points = [(-size, -size), (-size, size), (size,size), (size, -size)]
    moment = pm.moment_for_poly(int(mass), points, (0,0))

    body = pm.Body(mass, moment)
    body.position = pos

    shape = pm.Poly(body, points, (0,0))
    shape.friction = 1
    space.add(body,shape)

    return shape

def draw_box(screen, box):
    ps = box.get_points()
    ps.append(ps[0])
    ps = map(to_pygame, ps)
    pygame.draw.polygon(screen, THECOLORS["blue"], ps, 3)


def main():
    pygame.init()
    screen = pygame.display.set_mode((600, 600))
    pygame.display.set_caption("Piling boxes")
    clock = pygame.time.Clock()

    boxes = []
    x = 170
    y = 120
    space = pm.Space()
    space.gravity = (0.0, -100.0)

    ### ground
    body = pm.Body()
    shape = pm.Segment(body, (150,100), (450,100), .0)
    shape.friction = 4.4
    space.add(shape)

    for i in range(5):
        # what is the mass of the box?
        mass = randint(1,3)
        # what size is the box?
        size = randint(10, 35)
        # calculate its position & hold it in a Vec2d

        #x = x + size + 10
        y = y + size
        pos = Vec2d(x,y)

        box = add_box(space, size, pos, mass)
        boxes.append(box)

    while 1:
        clock.tick(15)
        space.step(1/30.0)

        for event in pygame.event.get():
            if event.type == QUIT:
                pygame.quit()
                sys.exit(0)
            elif event.type == KEYDOWN:
                if event.key == K_ESCAPE:
                    pygame.quit()
                    sys.exit(0)

        screen.fill(THECOLORS["white"])
        test_image = pygame.image.load("grass.png")

        screen.blit(test_image, to_pygame((450,100)), to_pygame((150,100)),3)


        for i in range(len(boxes)):
            draw_box(screen, boxes[i])

        pygame.display.flip()


if __name__ == '__main__':
    main()
4

4 回答 4

1

问题是

screen.blit(test_image, to_pygame((450,100)), to_pygame((150,100)),3)

要将表面blit 到屏幕,有效的blit 是:

screen.blit(test_image, (450,100))

所以你要:

screen.blit(test_image, to_pygame((450,100)))

注意:额外的 args 让我觉得您可能正在尝试使用源 rect 参数来使用图块集。但在那种情况下,您不会两次将世界转换为屏幕坐标。只是在目的地,而不是来源。

如果你确实想要 spritesheet/tileset,那么如何从 python 中的 sprite sheet 中选择 sprite image?Pygame.org/cookbook/SpriteSheet

于 2013-03-30T17:26:08.923 回答
1

没有回溯或错误日志,因此很难确定错误点,有根据的猜测是您在某处错误地传递了 Rectstyle 参数。请参阅 pygame.Rect 的文档,了解如何正确传递 Rectstyle 参数

pygame.Rect(left, top, width, height): return Rect
pygame.Rect((left, top), (width, height)): return Rect
pygame.Rect(object): return Rect
于 2013-03-30T14:23:19.390 回答
1

第三个参数blit是源area参数,应该是一个矩形,而不是坐标:

screen.blit(test_image, to_pygame((450,100)), to_pygame((150,100)),3)

也许你想要这个:

screen.blit(test_image, to_pygame((450,100)), pygame.Rect((0,0), (150,100)), 3)
于 2013-03-30T19:20:56.857 回答
0

问题是因为您的调用screen.blit不正确。见这里

电话可能是

screen.blit(test_image, to_pygame((450,100)))

或者如果你想使用 area 参数,

screen.blit(test_image, to_pygame((450,100)), pygame.Rect((0,0), (150,100)), 3)

此外,您在每个循环中加载guess.png,而不是将其移出while循环,您的代码将执行得更好。

于 2013-03-31T07:40:28.303 回答