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我有以下希望通过 jquery-ajax 调用的Web 方法。

[System.Web.Services.WebMethod]
public static int saveDataToServer(string cntName, string cntEmail, string cntMsg)
{
     // Implementation
}

这是我的jquery ajax 调用方法...

    function makeAjaxCall(arrOfObjName, arrOfObjValues, urlToCall) {
        debugger;
        var tempData;
        // Check if objNames's length is same as objValues's length.
        if (arrOfObjName.length != arrOfObjValues.length) {
            return null;
        }
        var dataString = "";
        // Building data object, we know the two arrays have same length!
        for (var intIndex = 0; intIndex < arrOfObjName.length; ++intIndex) {
            if (intIndex == arrOfObjName.length - 1) {
                dataString += arrOfObjName[intIndex] + ":" + arrOfObjValues[intIndex];
                continue;
            }
            dataString += arrOfObjName[intIndex] + ":" + arrOfObjValues[intIndex] + ",";
        }
        $.ajax({
            type: "POST",
            url: urlToCall,
            contentType: "application/json; charset=utf-8",
            data: JSON.stringify("{" + dataString + "}"),
            dataType: "json",
            success: function (data) {
                tempData = data;
            },
            error: function (data) {
                tempData = null;
            }
        });
        return tempData;
    }

在调用该方法之前，我将其传递给数组，

 var arrOfObjects = new Array("cntName", "cntEmail", "cntMsg");
 var arrOfObjectVals = new Array($(cntName).val(),$(cntEmail).val(),$(cntMsg).val());

但是当实际调用发生时，我在 Fiddler 中收到以下错误。

{"Message":"Cannot convert object of type \u0027System.String\u0027 to type \u0027System.Collections.Generic.IDictionary`2[System.String,System.Object]\u0027","StackTrace":" at System.Web.Script.Serialization.ObjectConverter.ConvertObjectToTypeInternal(Object o, Type type, JavaScriptSerializer serializer, Boolean throwOnError, Object\u0026 convertedObject)\r\n at System.Web.Script.Serialization.ObjectConverter.ConvertObjectToTypeMain(Object o, Type type, JavaScriptSerializer serializer, Boolean throwOnError, Object\u0026 convertedObject)\r\n at System.Web.Script.Serialization.JavaScriptSerializer.Deserialize(JavaScriptSerializer serializer, String input, Type type, Int32 depthLimit)\r\n at System.Web.Script.Serialization.JavaScriptSerializer.Deserialize[T](String input)\r\n at System.Web.Script.Services.RestHandler.GetRawParamsFromPostRequest(HttpContext context, JavaScriptSerializer serializer)\r\n at System.Web.Script.Services.RestHandler.GetRawParams(WebServiceMethodData methodData, HttpContext context)\r\n at System.Web.Script.Services.RestHandler.ExecuteWebServiceCall(HttpContext context, WebServiceMethodData methodData)","ExceptionType":"System.InvalidOperationException"}

我假设该方法在将“字符串类型数据”转换为字典时遇到问题。但为什么首先如此呢？我可以不构建我希望动态传递给网络方法的数据吗？

按要求更新：

>> JSON.stringify("{" + dataString + "}")

""{cntName:asdasdasd,cntEmail:abijeet.p@osmosys.asia,cntMsg:saveDataToServersaveDataToServersaveDataToServersaveDataToServersaveDataToServersaveDataToServersaveDataToServer}""
4

2 回答 2

1

您正在构建一个字符串dataString，您应该构建一个对象，然后将该对象转换为 json。就像是

    var dataString = {};
    // Building data object, we know the two arrays have same length!
    for (var intIndex = 0; intIndex < arrOfObjName.length; ++intIndex) {
        dataString[arrOfObjName[intIndex]] = arrOfObjValues[intIndex];
    }
    $.ajax({
        type: "POST",
        url: urlToCall,
        contentType: "application/json; charset=utf-8",
        data: JSON.stringify( dataString ),
        dataType: "json",
        success: function (data) {
            tempData = data;
        },
        error: function (data) {
            tempData = null;
        }
    });
于 2013-03-29T20:58:40.017 回答
1

我将继续添加这个作为答案：你自己做了太多的工作，让框架来做所有这些事情！

http://encosia.com/asp-net-web-services-mistake-manual-json-serialization/

您的 AJAX 调用只需这样......无需自己制作 JSON 字符串！

    $.ajax({
        type: "POST",
        url: urlToCall,
        contentType: "application/json; charset=utf-8",
        data: arrOfOBJECTS, //looky here! 
        dataType: "json",
        success: function (data) {
            tempData = data;
        },
        error: function (data) {
            tempData = null;
        }
    });

然后在您的后端服务上，将签名更改为类似这样的内容......

[System.Web.Services.WebMethod]
public static int saveDataToServer(string[] myArray)
{
     // Implementation
}

仅，使用一些与您的 JSON 对象匹配的结构或对象。不要自己做这项工作。我确实花了几天时间才弄清楚这一点，但当你这样做时，它就是美丽。

于 2013-03-29T22:47:48.077 回答