3

从另一个视图中渲染视图时，我收到一个 JS 错误“未捕获的 ReferenceError：模型未定义”。

我有一个列表视图：

define([
    'jquery', 
    'backbone',
    'underscore',
    'views/action',
    'collections/actionlist',
    'text!templates/actionlist.html'],

function($, Backbone, _, actionView, actionList, template){

var someactions = [
    { the_action: "Contact 1", due: "1, a street, a town, a city, AB12 3CD", list: "0123456789" },
    { the_action: "Contact 2", due: "1, a street, a town, a city, AB12 3CD", list: "0123456789" },
    { the_action: "Contact 3", due: "1, a street, a town, a city, AB12 3CD", list: "0123456789" }
];

var actionlistView = Backbone.View.extend({

    el: '#main',
    template: _.template(template),

    initialize: function () {
        this.collection = new actionList(someactions);            
        this.collection.on("add", this.renderAction, this);
    },

    events: {
        "click #add": "addAction"
    },

    render: function () {
        var $el = $('#main')

        $el.html(this.template);

        // Get Actions
        _.each(this.collection.models, function (action) {
            this.renderAction(action);
        }, this);

    },

    renderAction: function (action) {
        var theAction = new actionView({ model: action });
        $('#actionlist').append(theAction.render().el);
    },

    addAction: function(e){
        e.preventDefault();
        var formData = {};

        $('#addAction').children("input").each(function(i, el){
            if ($(el).val() !== "") {
                formData[el.id] = $(el).val();
            }
        });

        this.collection.create(formData);
    }
});

return actionlistView;
});

这个在 renderAction 函数中调用的 actionView 是：

define([
    'jquery', 
    'backbone',
    'underscore',
    'models/action',
    'text!templates/action.html'], 

function($, Backbone, _, actionModel, template){

var actionView = Backbone.View.extend({
    tagname: 'li',
    template: _.template(template),

    render: function () {
        this.$el.html(this.template(this.model)); // ERROR OCCURS ON THIS LINE
        return this;
    }
});

return actionView;
});

我在“this.$el.html(this.template(this.model));”这一行得到错误 尝试渲染第一个 actionView 时。

我难住了！！我错过了什么？

按要求操作视图模板：

    <b class="name"><%=model.get("the_action")%></b> - <%=model.get("due")%> - 
    <em>from <%=model.get("list")%></em>
4

1 回答 1

3

您最好在模板中调用 model.toJSON() 并在模板中引用 json。

由此：

this.$el.html(this.template(this.model));

对此：

this.$el.html(this.template(this.model.toJSON()));

然后直接在模板中引用'due'和'list'：

<b class="name"><%=the_action%></b> - <%=due%> - 
    <em>from <%=list%></em>
于 2013-03-29T19:45:40.493 回答