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问题：如何从列表中删除第一个单词以添加到名为的新列表中car_list，并保留其余单词以添加到另一个列表中other_list。

在other_list我把剩下的放进字典里

比如当我阅读文件时，我得到类似的东西

data_file = ['1911 Overland OctoAuto', '1913 Scripps-Booth Bi-Autogo','1920 Briggs and Stratton Flyer'

car_list = [] other_list = []

我如何得到如下结果

car_list = [Overland, Scripps-Booth, Briggs]

other_list = [1911,OctoAuto, 1913, Bi-Autogo, 1920, and Stratton flyer]

这是我所拥有的

data_file = open("facts.txt", 'r')


def clean_list(data_file):
    new_list =[]
    clean_list =[]
    car_list = []
    other_list = []
    D = {}
    for i in data_file:
        new_list = data_file.split('\n') #change split by new line or word

    clean_list = [(x.strip(' ')) for x in new_list]
    car_list = (clean_list.strip().split(' ')[2:], ' ') 
    other_list = dict(zip(keys, values))# Just an example
    return car_list

car_list = clean_list(data_file)

我想car_list = (clean_list.strip().split(' ')[2:], ' ')

会工作，但我收到以下错误。

car_list = (clean_list.lstrip().split(' ')[2:], ' ')

AttributeError: 'list' object has no attribute 'split'

AttributeError: 'list' object has no attribute 'lstrip'

我认为通过拼接会起作用，但没有骰子。

我试过car_list = clean_list.split(' ',2)[2]了，什么也没打印

有任何想法吗？我知道文件正在被读取，但我只是不知道该怎么做。

4

3 回答 3

5

我对您的警告是，这other_list看起来像是不同类型数据的混合。这通常是不明智的。有了这个免责声明，这里有一个尝试：

data_file = ['1911 Overland OctoAuto', 
             '1913 Scripps-Booth Bi-Autogo',
             '1920 Briggs and Stratton Flyer']

car_list = []
other_list = []
for entry in data_file:
    year, make, model = entry.split(' ',2)
    car_list.append(make)
    other_list.append(year)
    other_list.append(model)

print car_list
>>>> ['Overland', 'Scripps-Booth', 'Briggs']
print other_list
>>>> ['1911', 'OctoAuto', '1913', 'Bi-Autogo', '1920', 'and Stratton Flyer']
于 2013-03-28T21:19:33.143 回答
1

最终，您也可以使用正则表达式来拆分字符串。

import re
data_file = ['1911 Overland OctoAuto', 
             '1913 Scripps-Booth Bi-Autogo',
             '1920 Briggs and Stratton Flyer']

car_list = []
other_list = []
delimiter_space = re.compile(' ')
for entry in data_file:
    year, make, model = delimiter_space.split(entry,maxsplit=2)
    car_list.append(make)
    other_list.append(year)
    other_list.append(model)

print car_list
>>>> ['Overland', 'Scripps-Booth', 'Briggs']
print other_list
>>>> ['1911', 'OctoAuto', '1913', 'Bi-Autogo', '1920', 'and Stratton Flyer']
于 2013-03-28T21:21:55.390 回答
1 
T = [x.split(' ', 2) for x in data_file]
car_list = [ x[1] for x in T]
other_list =  [ v for x in T for v in x if v != x[1]]
print car_list
print other_list

输出

['Overland', 'Scripps-Booth', 'Briggs']
['1911', 'OctoAuto', '1913', 'Bi-Autogo', '1920', 'and Stratton Flyer']
于 2013-03-28T21:48:44.860 回答