1

我正在尝试使用 QLineEdit 小部件从用户那里检索一些值。当 QPushButton 引发单击事件时,我希望从所有 QLineEdit 小部件中检索文本并将其存储在本地 MySQL 数据库中。但是,当我尝试在插入语句中使用字符串替换时,这些值不会被替换。这是我的sql语句:

sql = 'INSERT INTO jobs (incident_id, organization, organization_poc, media_type) VALUES ("%s", "%s", "%s", "%s")' % (self.edi_IncidentID.text(), self.edi_OrganizationAffected.text(), self.edi_OrganizationContact.text(), self.edi_MediaType.text())

所有 self.edi_xxx 变量都只是 QLineEdit 小部件。当按下按钮时,会触发以下内容:

self.connect(btn_Submit, QtCore.SIGNAL('clicked()'), self.submitForm)  

提交所做的只是创建一个数据库对象并将值写入数据库。然而,为了调试,我打印出构建的 SQL 语句,结果如下:INSERT INTO jobs (incident_id, organization, organization_poc, media_type) VALUES ("", "", "", "")。

我也尝试使用 str() 函数将 QString 转换为字符串,但同样的事情发生了。

任何帮助将不胜感激 :)?

大号

编辑:这是减去导入的完整代码:

class Database():
def __init__(self):
   self.db_host = "localhost"
   self.db_user = "***********"
   self.db_pass = "***********"
   self.db_name = "incidents"

def openConn(self):
   self.db = MySQLdb.connect(self.db_host, self.db_user, self.db_pass, self.db_name)

def closeConn(self):
   self.db.close()

def writeValues(self, sql):
   self.openConn()
   self.cursor = self.db.cursor()
   self.cursor.execute(sql)
   self.cursor.fetchone()
   self.closeConn()

class NewIncidentForm(QtGui.QWidget):
def __init__(self, parent=None):
    QtGui.QWidget.__init__(self, parent)

    self.setWindowTitle('New Incident')

    lbl_IncidentID = QtGui.QLabel('Incident ID:')
    lbl_MediaType = QtGui.QLabel('Media Type:')
    lbl_OrganizationAffected = QtGui.QLabel('Organization Affected:')
    lbl_OrganizationContact = QtGui.QLabel('Organization Point of Contact: ')

    self.edi_IncidentID = QtGui.QLineEdit()
    self.edi_MediaType = QtGui.QLineEdit()
    self.edi_OrganizationAffected = QtGui.QLineEdit()
    self.edi_OrganizationContact = QtGui.QLineEdit()


    btn_Submit = QtGui.QPushButton('Submit')

    grid = QtGui.QGridLayout()
    grid.setSpacing(10)

    grid.addWidget(lbl_IncidentID, 1, 0)
    grid.addWidget(self.edi_IncidentID, 1, 1)

    grid.addWidget(lbl_MediaType, 3, 0)
    grid.addWidget(self.edi_MediaType, 3, 1)

    grid.addWidget(lbl_OrganizationAffected, 4, 0)
    grid.addWidget(self.edi_OrganizationAffected, 4, 1)

    grid.addWidget(lbl_OrganizationContact, 5, 0)
    grid.addWidget(self.edi_OrganizationContact, 5, 1)

    grid.addWidget(btn_Submit, 15, 0)

    self.sql = 'INSERT INTO jobs (incident_id, organization, organization_poc, media_type) VALUES ("%s", "%s", "%s", "%s")' % (self.edi_IncidentID.text(), self.edi_OrganizationAffected.text(), self.edi_OrganizationContact.text(), self.edi_MediaType.text())
    self.connect(btn_Submit, QtCore.SIGNAL('clicked()'), self.submitForm)        

    self.setLayout(grid)
    self.resize(350, 300)

def submitForm(self):
    db = Database()
    db.writeValues(self.sql)

app = QtGui.QApplication(sys.argv)
qb = NewIncidentForm()
qb.show()
sys.exit(app.exec_())
4

3 回答 3

1

:D QString 有__str__功能所以试试这个:

self.sql = 'INSERT INTO jobs (incident_id, organization, organization_poc, media_type) VALUES ("%s", "%s", "%s", "%s")' % (''.join(self.edi_IncidentID.text()), ''.join(self.edi_OrganizationAffected.text()), ''.join(self.edi_OrganizationContact.text()), ''.join(self.edi_MediaType.text()))

添加''.join()

或者 QString 有 toUtf8()

所以self.edi_IncidentIS.text()改为:

self.edi_IncidentIS.text().toUtf8()

整个指令:

self.sql = 'INSERT INTO jobs (incident_id, organization, organization_poc, media_type) VALUES ("%s", "%s", "%s", "%s")' % (self.edi_IncidentID.text().toUtf8(), self.edi_OrganizationAffected.text().toUtf8(), self.edi_OrganizationContact.text().toUtf8(), self.edi_MediaType.text().toUtf8())
于 2009-11-28T19:31:35.253 回答
1

该程序缺少的另一部分是在脚本请求时存储数据的 commit() 函数或 autocommit(true)

def closeConn(self):
self.db.close()
self.db.commit()

def submitForm(self):
db = Database()
self.sql = 'INSERT INTO jobs (incident_id, organization, organization_poc, media_type) VALUES ("%s", "%s", "%s", "%s")' % (self.edi_IncidentID.text(), self.edi_OrganizationAffected.text(), self.edi_OrganizationContact.text(), self.edi_MediaType.text())      
db.writeValues(self.sql)
于 2013-09-14T17:31:08.653 回答
1

原因很简单:

self.sql 应该在 def submitForm(self) 中:

不在 def init (self, parent=None) 中:

因为否则它是无效的!

于 2011-03-03T20:27:10.213 回答