12

使用 C#.Net 4.5、Visual Studio 2012 Ulti、WPF。

我有一些旧的 win-forms 代码，我想在这个新的 WPF 应用程序中执行这些代码。

代码如下：

DataGridViewImageCell pNew = new DataGridViewImageCell();

ParetoGrid.Columns.Add(new DataGridViewImageColumn() { CellTemplate = pNew, FillWeight = 1, HeaderText = "pNew", Name = "pNew", Width = 30 });

ParetoGrid.Columns["pNew"].DisplayIndex = 18;

3 行代码添加一个可以处理图像的列。在 WPF 中，我看到它有点不同。我需要添加“图像列”吗？或者 WPF 列是否支持图像？还是有另一种语法不同的 3 班轮解决方案？

谢谢你们的帮助

4

4 回答 4

19

看到这个答案：

WPF DataGrid 中的图像列

 <DataGridTemplateColumn Header="Image" Width="SizeToCells"
 IsReadOnly="True">
   <DataGridTemplateColumn.CellTemplate>
      <DataTemplate>
           <Image Source="{Binding Image}" />
      </DataTemplate>
    </DataGridTemplateColumn.CellTemplate>
 </DataGridTemplateColumn>

在代码中添加一列之后：

DataGridTextColumn textColumn1 = new DataGridTextColumn();
textColumn1.Header = "Your header";
textColumn1.Binding = new Binding("YourBindingField");
dg.Columns.Add(textColumn1);

用于DataGridTemplateColumn添加自定义列请参阅：如何以编程方式在 wpf datagrid 列中显示图像？

于 2013-03-28T13:39:58.963 回答
5

这就是我所做的。使用这样的图像控件在数据网格中添加数据模板

            <DataGridTemplateColumn Header="File Type" Width="*">
                <DataGridTemplateColumn.CellTemplate>
                    <DataTemplate>
                        <Image Height="25" Width="50" Source="{Binding FileIcon}"  />
                    </DataTemplate>
                </DataGridTemplateColumn.CellTemplate>
            </DataGridTemplateColumn>

如您所见，我正在将 Image 与一个名为“FileIcon”的属性绑定，该属性在类版本中使用，如下所示

            public class Version
            {
              public string FileIcon { get; set; }
            }

现在您要做的就是绑定提供“FileIcon”的路径并像这样更新DataGrid的ItemSource

            ObservableCollection<Version> items = new ObservableCollection<Version>();

            items.Add(new Version()
            {
                FileIcon = "/AssemblyName;component/Images/eye.png",
            });
            YourDataGrid.ItemsSource = null;
            YourDataGrid.ItemsSource = items;
于 2018-10-24T05:10:13.683 回答
2

这是 MainWindow.xaml 的代码，只是为了更好地理解

`

<Window x:Class="Pic_in_Datagrid.MainWindow"
        xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
        xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
        xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
        xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
        xmlns:local="clr-namespace:Pic_in_Datagrid"
        mc:Ignorable="d"
        Title="MainWindow" Height="350" Width="525">

    <Grid>
        <DataGrid x:Name="dt1" ColumnWidth="*" AutoGenerateColumns="False">

        </DataGrid>
    </Grid>
</Window>

之后是我的 MainWindow.xaml.cs 的图像或文本代码，用于动态添加 datadrid ......

using System;
using System.Collections.Generic;
using System.IO;
using System.Windows;
using System.Windows.Data;
using System.Windows.Media.Imaging;
using System.Windows.Controls;    
namespace Pic_in_Datagrid
        {
            /// <summary>
            /// Interaction logic for MainWindow.xaml
            /// </summary>
            public partial class MainWindow : Window
            {
                public StudentData stu_data { get; set; }
                public MainWindow()
                {
                    InitializeComponent();
                    stu_data = new StudentData();

                    List<StudentData> stu = new List<StudentData>();
                    stu.Add(new StudentData() { image = toBitmap(File.ReadAllBytes(@"D:\1.jpg")), stu_name = "abc" });
                    stu.Add(new StudentData() { image = toBitmap(File.ReadAllBytes(@"D:\1.jpg")), stu_name = "def" });



                    FrameworkElementFactory factory = new FrameworkElementFactory(typeof(System.Windows.Controls.Image));
                    Binding bind = new System.Windows.Data.Binding("image");//please keep "image" name as you have set in your class data member name
                    factory.SetValue(System.Windows.Controls.Image.SourceProperty, bind);
                    DataTemplate cellTemplate = new DataTemplate() { VisualTree = factory };
                    DataGridTemplateColumn imgCol = new DataGridTemplateColumn()
                    {
                        Header = "image", //this is upto you whatever you want to keep, this will be shown on column to represent the data for helping the user...
                        CellTemplate = cellTemplate
                    };
                    dt1.Columns.Add(imgCol);

                    dt1.Columns.Add(new DataGridTextColumn()
                    {
                        Header = "student name",
                        Binding = new Binding("stu_name") //please keep "stu_name" as you have set in class datamember name
                    });

                    dt1.ItemsSource = stu;    
                }

                public static BitmapImage toBitmap(Byte[] value)
                {
                    if (value != null && value is byte[])
                    {
                        byte[] ByteArray = value as byte[];
                        BitmapImage bmp = new BitmapImage();
                        bmp.BeginInit();
                        bmp.StreamSource = new MemoryStream(ByteArray);
                        bmp.EndInit();
                        return bmp;
                    }
                    return null;
                }
            }

           public class StudentData
           {
                    public BitmapImage image { get; set; }
                    public string stu_name { get; set; }
            }
        }

以上所有代码均取自不同的资源...感谢开发和共享这些代码的他们...

于 2016-12-08T05:28:07.690 回答
0

您可以尝试通过以下模式将 Image 添加到 DataGridTextColumn。您可以排序并复制到剪贴板效果很好。使用您的转换器，或绑定到您的财产。

<DataGridTextColumn  Header="Level"  IsReadOnly="True" Binding="{Binding Level,Converter={StaticResource LogLevelStringConverter}}"   >
    <DataGridTextColumn.CellStyle>
        <Style TargetType="DataGridCell" >
            <Setter Property="Template">
                <Setter.Value>
                    <ControlTemplate TargetType="DataGridCell">
                        <Grid Background="{TemplateBinding Background}" >
                            <ContentPresenter VerticalAlignment="Center" Margin="20,0,0,0" HorizontalAlignment="Left"  />
                            <Image Grid.Column="0" Width="18" Height="18" Source="{Binding Level,Converter={StaticResource LogLevelIconConverter}}"  HorizontalAlignment="Left" />
                        </Grid>
                    </ControlTemplate>
                </Setter.Value>
            </Setter>
        </Style>
    </DataGridTextColumn.CellStyle>
</DataGridTextColumn>
于 2019-09-10T09:51:30.093 回答