ajax - _escape_fragment_ 的重写规则

Question

我想为

http://www.site.com/noticia/​​?_escaped_fragment_=noticia=/279/beto-cuevas3er-sencillo-dej-de-pensar

到：

http://www.site.com/noticia/​​#!noticia=/279/beto-cuevas3er-sencillo-dej-de-pensar

我已经尝试过了，但离我需要的还很远，对吧？

# Enable Rewrite Engine
RewriteEngine on

#Create friendly URL
RewriteRule ^index.php?_escaped_fragment=something=yes$ 
index.php/#!something=yes [L]

Answer 1

通过启用 mod_rewrite 和 .htaccess httpd.conf，然后将此代码放在您.htaccess的DOCUMENT_ROOT目录下：

Options +FollowSymLinks -MultiViews
# Turn mod_rewrite on
RewriteEngine On
RewriteBase /

RewriteCond %{QUERY_STRING} ^_escaped_fragment_=([^=]+)=([^&]+) [NC]
RewriteRule ^$ /%1/#!%1=%2? [L,R,NE]