我正在尝试从用于填充 xml 的列中删除方形字符 问题是 xml 没有正确创建，并且为我创建了很多工作。因此，作为每天的脚本作业，我将尝试运行 sql 来更新值以删除有问题的字符。
到目前为止我有
select * from (select dump(narration) as dn,narration from ar_journal)
where dn like '%27%'
and dn not like '%=27:%';
这找到了有问题的东西，但我想知道是否可以使用替换函数调用 dn？
请注意，dn 是列旁白的转储。
结果如下 DN Typ=1 Len=200: 96,27,97,110,115,102,101,114,32,102,114,111,109,32,67,117,115,116,111,109,101,114,32,32,32,32,32,75,42,32,323, ,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32 ,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32 ,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32 ,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32 ,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32 ,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32 ,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32
旁白
CharWasHere '从客户 900转移
值是不可预测的，但字符始终相同，
任何帮助将不胜感激。
干杯，
本