这是我的数据库中搜索框的编码，但是当我运行它时，它显示错误通知：未定义变量：在第 15 行的 /opt/lampp/htdocs/1234.php 中搜索然后 ii 在我的搜索框中键入任何内容它说对象未找到！
在此服务器上找不到请求的 URL。引用页面上的链接似乎是错误的或过时的。请将该错误通知该页面的作者。
如果您认为这是服务器错误，请联系网站管理员。
错误 404
本地主机 Apache/2.4.3 (Unix) OpenSSL/1.0.1c PHP/5.4.7
<html>
<h2>Search</h2>
<form name="search" method="post" action="<?=$PHP_SELF?>">
Seach for: <input type="text" name="find" /> in
<Select NAME="field">
<Option VALUE="fname">diseasename</option>
<Option VALUE="lname">genename</option>
</Select>
<input type="hidden" name="searching" value="yes" />
<input type="submit" name="search" value="Search" />
</form>
</html>
<?php
//This is only displayed if they have submitted the form
if ($searching =="yes")
{
echo "<h2>Results</h2><p>";
//If they did not enter a search term we give them an error
if ($find == "")
{
echo "<p>You forgot to enter a search term";
exit;
}
// Otherwise we connect to our Database
mysql_connect("localhost", "root", "****") or die(mysql_error());
mysql_select_db("missensencemuttation") or die(mysql_error());
// We preform a bit of filtering
$find = strtoupper($find);
$find = strip_tags($find);
$find = trim ($find);
//Now we search for our search term, in the field the user specified
$data = mysql_query("SELECT * FROM users WHERE upper($field) LIKE'%$find%'");
//And we display the results
while($result = mysql_fetch_array( $data ))
{
echo $result['fname'];
echo " ";
echo $result['lname'];
echo "<br>";
echo $result['info'];
echo "<br>";
echo "<br>";
}
//This counts the number or results - and if there wasn't any it gives them a little message explaining that
$anymatches=mysql_num_rows($data);
if ($anymatches == 0)
{
echo "Sorry, but we can not find an entry to match your query<br><br>";
}
//And we remind them what they searched for
echo "<b>Searched For:</b> " .$find;
}
?>
我不知道我在脚本中做错了什么。我是 php 的初学者，我正在使用互联网参考来获取 php 的知识。可以纠正这个脚本