c++ - cin.Getline 不返回任何内容

Question

我正在努力学习 C++。我现在在弦上。我写了这个简单的方法，它应该要求输入一个字符串然后返回它。为此，我使用 cin.getLine() 方法，但使用 cin.getLine() 后未打印字符串

string getString(char string[])
{

  cout << "Please enter a string to process ";
  cin >> string;
  cout << "String in getString before process: " << string << "\n";
  cin.getline(string, STRINGSIZE);
  cout << "String after processing: " << string << "\n"; // here string is not printed
  return string;
}

谁能帮我理解我做错了什么？谢谢

Answer 1

您首先将字符串读取到std::stringwith cin >> string;，然后再从cinwith读取一些内容，cin.getline(string, STREAMSIZE); 这是不必要的，读取一次并返回：

string getString(char string[]){
  cout << "Please enter a string to process ";
  cin >> string;
  cout << "String in getString before process: " << string << "\n";
  // process this, do whatever you describe as processing it
  cout << "String after processing: " << string << "\n"; // string is printed
  return string;
 }

否则，如果您想使用getline，请执行以下操作：

  std::string name;

  std::cout << "Please, enter your full name: ";
  std::getline (std::cin,name); // or std::getline(std::cin,string, 'r'); to read
  //only to delimiter character 'r'
  std::cout << "Hello, " << name << "!\n";

所以要记住的是使用getlineOR cin，除非真的有特殊原因，否则不要同时使用