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我在两个安卓设备之间有一个网络，一个设备只会发送一个块的位置，然后连接到手机的客户端将使用这些位置来显示块，主机可以移动块，客户端可以看到这个，但是在随机的时间后，连接就会断开，但我不确定它是连接还是 doInBackground 方法。

这是引起我问题的方法

@Override
protected Object doInBackground(Object... params)
{
    setUpClient();
    if( host == true ) { server.execute(); }
    rdyForPlay = true;
    boolean run = true;
    while( run )
    {
        //Tell the server to give position of players
        if( host == false)
        {
            Log.d(TAG, "Running client doInBackgroundMethod");
            try {
                if(socket == null)
                {
                    socket = new DatagramSocket( port );
                }
                byte[] bufer = new byte[256];
                String msg = "position";
                int msgLength = msg.length();
                bufer = msg.getBytes();
                InetAddress address;
                address = InetAddress.getByName("192.168.1.59");
                DatagramPacket p = new DatagramPacket( bufer, bufer.length , address, port );
                socket.send( p );

            } catch (UnknownHostException e2) {
                // TODO Auto-generated catch block
                e2.printStackTrace();
            } catch (SocketException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            } catch (IOException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }

            byte[] buf = new byte[256];
            DatagramPacket packet = new DatagramPacket( buf, buf.length );
            try 
            {
                socket.receive( packet );
            } 
            catch (IOException e) 
            {
                Log.d(TAG, "Error with receiving data");
                e.printStackTrace();
            }

            String data = new String( buf, 0, packet.getLength() );
            Log.d(TAG, "Data received is in run method:" + data);
            //Take the data from the server and use it
            String[] pos = data.split(":");
            assets.get(0).setPosition( Integer.parseInt( pos[0] ), Integer.parseInt( pos[1] ) );
            //ID = Integer.parseInt( data );
        }
    }
    return null;
}

如果需要，可以提供更多代码。

帆布

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