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我正在尝试用 Java 制作一个基于文本的 Hangman。

这是我的 Java 代码：

package hangman;

import java.util.Random;
import java.util.Scanner;
import java.lang.String;

public class Hangman {

    public static void main(String[] args) {
        // TODO code application logic here
        Scanner chez = new Scanner(System.in);
        Scanner waffle = new Scanner(System.in);
        Random randomGenerator = new Random();
        StringBuilder displayWord = new StringBuilder("______________________________");
        String theWord = null;
        String preLetter;
        //String sbDisplayWord;
        char letter = 0;
        int randomNumber;
        int lengthOfWord;
        int numberOfLetterInWord = 0;
        int gDisplay;
        int guessWordNumber = 0;
        String guessWord;
        RandomWord troll = new RandomWord();    
        randomNumber = randomGenerator.nextInt(12);
        //Fill var with the word.
        theWord = troll.wordDecide(randomNumber);

        System.out.println ("Welcome to Hangman!");

        lengthOfWord=theWord.length( );
        System.out.println("This word has " + lengthOfWord + " letters.");

        System.out.println("You have 20 guesses.");

        for (int g =19; g >= 0; g--) {    

            System.out.println("If you want to guess the word, type 0. If you want to guess a letter, type 1.");
            guessWordNumber=chez.nextInt();

            if (guessWordNumber==0) {
                System.out.println("Enter the word now. Remember, don't capitalize it.");
                guessWord=waffle.nextLine();
                if (guessWord.equals(theWord)) {
                    System.out.println("YOU WIN");
                    System.exit(0);
                } else {
                    System.out.println("Sorry, this wasn't the correct word.");
                }
            } else if (guessWordNumber==1) {

                System.out.println("Please enter the letter you wish to guess with.");
                //System.out.println("It will tell you if you have guessed right for any of the letters. If it is blank, that means none of the letters match.");
                preLetter=chez.nextLine();
                letter=preLetter.charAt(0);
                System.out.println("");
                for(int i = 0; i <= lengthOfWord -1; i++ ) {     //-Eshan

                    if (letter == theWord.charAt( i )) {

                        numberOfLetterInWord=i+1;
                        System.out.println("This letter matches with letter number " + numberOfLetterInWord + " in the word.");
                        displayWord.setCharAt(i, letter);
                    } else {

                        numberOfLetterInWord=i+1;
                        System.out.println("This letter doesn't match with letter number " + numberOfLetterInWord + " in the word.");

                    }       


                }

                System.out.println("");
                System.out.println("The word so far is " + displayWord);
                System.out.println("");
                gDisplay = g + 1;
                System.out.println("You have " + gDisplay + " guesses left.");

            } else {
                System.exit(0);
            }

        }

        System.out.println("GAME OVER");
        System.exit(0);

    }
}



package hangman;

public class RandomWord {
    private static String[] wordArray = {
        "psychology",
        "keratin",
        "nostalgia",
        "pyromaniac",
        "chlorophyl",
        "derivative",
        "unitard",
        "pterodactyl",
        "xylophone",
        "excommunicate",
        "obituary",
        "infinitesimal",
        "concupiscent",
    };

    public String wordDecide(int randomNumber) {
        String theWord;
        theWord = wordArray[randomNumber];
        return theWord;
    }

}

Netbeans 给了我这个错误：

线程“主”java.lang.StringIndexOutOfBoundsException 中的异常：字符串索引超出范围：
java.lang.String.charAt(String.java:695)
处 hangman.Hangman.main(Hangman.java:56)
Java 结果中的 0： 1

4

2 回答 2

2

当您调用charAt(0)长度为 0 的字符串时，可能会发生这种情况。您应该在调用该方法之前检查该字符串是否为空。

于 2013-03-26T23:56:30.473 回答
0

StringIndexOutOfBoundsException由于这条线，你得到了一个

guessWordNumber = chez.nextInt();

不消耗换行符并将字符传递到行

preLetter = chez.nextLine();

然后它不会阻塞，因为它已经收到了输入。这会将一个空分配String给preLetter导致异常。您可以使用Scanner#nextLine来使用此字符：

guessWordNumber = Integer.parseInt(chez.nextLine());
于 2013-03-27T00:00:11.780 回答