我正在制作一个简单的地址簿应用程序（针对 4.2），它包含姓名、地址、城市、州、邮编和电话。
我想将输入的电话号码格式化为电话号码 (XXX) XXX-XXXX，但我需要将值作为字符串提取出来，以便在保存时将其存储在数据库中。我怎样才能做到这一点？？我为“电话号码”输入设置了 EditText，但这显然并没有做太多。
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151153 次
15 回答
107
只需使用PhoneNumberFormattingTextWatcher，只需调用：
editText.addTextChangedListener(new PhoneNumberFormattingTextWatcher());
另外
需要明确的是，PhoneNumberFormattingTextWatcher 的主干是PhoneNumberUtils 类。PhoneNumberUtils.formatNumber()不同之处在于 TextWatcher 维护 EditText，而您每次更改其内容时都必须调用它。
于 2013-03-26T21:07:57.870 回答
63
有一个名为PhoneNumberUtils的库可以帮助您处理电话号码的转换和比较。例如，使用...
EditText text = (EditText) findViewById(R.id.editTextId);
PhoneNumberUtils.formatNumber(text.getText().toString())
...以标准格式格式化您的号码。
PhoneNumberUtils.compare(String a, String b);
...有助于模糊比较。还有很多。查看http://developer.android.com/reference/android/telephony/PhoneNumberUtils.html了解更多信息。
ps 将 EditText 设置phone为已经是一个不错的选择；digits最终，在你的布局中添加它可能会有所帮助，它看起来像......
<EditText
android:id="@+id/editTextId"
android:inputType="phone"
android:digits="0123456789+"
/>
于 2013-03-26T21:09:56.380 回答
32
只需使用这个：
在 Java 代码中：
editText.addTextChangedListener(new PhoneNumberFormattingTextWatcher());
在 XML 代码中：
<EditText
android:id="@+id/etPhoneNumber"
android:inputType="phone"/>
这段代码对我有用。当编辑文本中的文本更改时，它将自动格式化。
于 2014-11-17T09:21:08.677 回答
22
我最近为 Android EditText 做了类似的格式，如 1 (XXX) XXX-XXXX。请在下面找到代码。只需使用 TextWatcher 子类作为文本更改侦听器： ....
UsPhoneNumberFormatter addLineNumberFormatter = new UsPhoneNumberFormatter(
new WeakReference<EditText>(mYourEditText));
mYourEditText.addTextChangedListener(addLineNumberFormatter);
...
private class UsPhoneNumberFormatter implements TextWatcher {
//This TextWatcher sub-class formats entered numbers as 1 (123) 456-7890
private boolean mFormatting; // this is a flag which prevents the
// stack(onTextChanged)
private boolean clearFlag;
private int mLastStartLocation;
private String mLastBeforeText;
private WeakReference<EditText> mWeakEditText;
public UsPhoneNumberFormatter(WeakReference<EditText> weakEditText) {
this.mWeakEditText = weakEditText;
}
@Override
public void beforeTextChanged(CharSequence s, int start, int count,
int after) {
if (after == 0 && s.toString().equals("1 ")) {
clearFlag = true;
}
mLastStartLocation = start;
mLastBeforeText = s.toString();
}
@Override
public void onTextChanged(CharSequence s, int start, int before,
int count) {
// TODO: Do nothing
}
@Override
public void afterTextChanged(Editable s) {
// Make sure to ignore calls to afterTextChanged caused by the work
// done below
if (!mFormatting) {
mFormatting = true;
int curPos = mLastStartLocation;
String beforeValue = mLastBeforeText;
String currentValue = s.toString();
String formattedValue = formatUsNumber(s);
if (currentValue.length() > beforeValue.length()) {
int setCusorPos = formattedValue.length()
- (beforeValue.length() - curPos);
mWeakEditText.get().setSelection(setCusorPos < 0 ? 0 : setCusorPos);
} else {
int setCusorPos = formattedValue.length()
- (currentValue.length() - curPos);
if(setCusorPos > 0 && !Character.isDigit(formattedValue.charAt(setCusorPos -1))){
setCusorPos--;
}
mWeakEditText.get().setSelection(setCusorPos < 0 ? 0 : setCusorPos);
}
mFormatting = false;
}
}
private String formatUsNumber(Editable text) {
StringBuilder formattedString = new StringBuilder();
// Remove everything except digits
int p = 0;
while (p < text.length()) {
char ch = text.charAt(p);
if (!Character.isDigit(ch)) {
text.delete(p, p + 1);
} else {
p++;
}
}
// Now only digits are remaining
String allDigitString = text.toString();
int totalDigitCount = allDigitString.length();
if (totalDigitCount == 0
|| (totalDigitCount > 10 && !allDigitString.startsWith("1"))
|| totalDigitCount > 11) {
// May be the total length of input length is greater than the
// expected value so we'll remove all formatting
text.clear();
text.append(allDigitString);
return allDigitString;
}
int alreadyPlacedDigitCount = 0;
// Only '1' is remaining and user pressed backspace and so we clear
// the edit text.
if (allDigitString.equals("1") && clearFlag) {
text.clear();
clearFlag = false;
return "";
}
if (allDigitString.startsWith("1")) {
formattedString.append("1 ");
alreadyPlacedDigitCount++;
}
// The first 3 numbers beyond '1' must be enclosed in brackets "()"
if (totalDigitCount - alreadyPlacedDigitCount > 3) {
formattedString.append("("
+ allDigitString.substring(alreadyPlacedDigitCount,
alreadyPlacedDigitCount + 3) + ") ");
alreadyPlacedDigitCount += 3;
}
// There must be a '-' inserted after the next 3 numbers
if (totalDigitCount - alreadyPlacedDigitCount > 3) {
formattedString.append(allDigitString.substring(
alreadyPlacedDigitCount, alreadyPlacedDigitCount + 3)
+ "-");
alreadyPlacedDigitCount += 3;
}
// All the required formatting is done so we'll just copy the
// remaining digits.
if (totalDigitCount > alreadyPlacedDigitCount) {
formattedString.append(allDigitString
.substring(alreadyPlacedDigitCount));
}
text.clear();
text.append(formattedString.toString());
return formattedString.toString();
}
}
于 2014-05-14T15:41:29.023 回答
15
也许下面的示例项目可以帮助您；
https://github.com/reinaldoarrosi/MaskedEditText
该项目包含一个视图类调用MaskedEditText。首先，您应该将它添加到您的项目中。
然后在项目的 res/values/attrs.xml 文件中添加下面的 xml 部分；
<resources>
<declare-styleable name="MaskedEditText">
<attr name="mask" format="string" />
<attr name="placeholder" format="string" />
</declare-styleable>
</resources>
然后你就可以使用MaskedEditText视图了。
最后，您应该在 xml 文件中添加 MaskedEditText，如下所示；
<packagename.currentfolder.MaskedEditText
xmlns:app="http://schemas.android.com/apk/res-auto"
android:id="@+id/maskedEditText"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:ems="10"
android:text="5"
app:mask="(999) 999-9999"
app:placeholder="_" >
当然，您可以通过编程方式使用它。
在这些步骤之后，添加MaskedEditText将如下所示；
以编程方式，如果您想将其文本值设为未屏蔽，您可以使用下面的行；
maskedEditText.getText(true);
要获取掩码值，您可以在方法中发送false值而不是值。truegetText
于 2016-07-27T10:18:54.260 回答
13
您需要创建一个类：
public class PhoneTextFormatter implements TextWatcher {
private final String TAG = this.getClass().getSimpleName();
private EditText mEditText;
private String mPattern;
public PhoneTextFormatter(EditText editText, String pattern) {
mEditText = editText;
mPattern = pattern;
//set max length of string
int maxLength = pattern.length();
mEditText.setFilters(new InputFilter[]{new InputFilter.LengthFilter(maxLength)});
}
@Override
public void beforeTextChanged(CharSequence s, int start, int count, int after) {
}
@Override
public void onTextChanged(CharSequence s, int start, int before, int count) {
StringBuilder phone = new StringBuilder(s);
Log.d(TAG, "join");
if (count > 0 && !isValid(phone.toString())) {
for (int i = 0; i < phone.length(); i++) {
Log.d(TAG, String.format("%s", phone));
char c = mPattern.charAt(i);
if ((c != '#') && (c != phone.charAt(i))) {
phone.insert(i, c);
}
}
mEditText.setText(phone);
mEditText.setSelection(mEditText.getText().length());
}
}
@Override
public void afterTextChanged(Editable s) {
}
private boolean isValid(String phone)
{
for (int i = 0; i < phone.length(); i++) {
char c = mPattern.charAt(i);
if (c == '#') continue;
if (c != phone.charAt(i)) {
return false;
}
}
return true;
}
}
如下使用它：
phone = view.findViewById(R.id.phone);
phone.addTextChangedListener(new PhoneTextFormatter(phone, "+7 (###) ###-####"));
于 2019-05-11T11:48:39.897 回答
4
按照此答案中的说明格式化 EditText 掩码。
之后，您可以使用以下方法从屏蔽字符串中捕获原始数字：
String phoneNumbers = maskedString.replaceAll("[^\\d]", "");
于 2016-01-20T18:26:00.720 回答
3
更像是干净的：
@Override
public void onTextChanged(CharSequence s, int start, int before, int count) {
String text = etyEditText.getText();
int textlength = etyEditText.getText().length();
if (text.endsWith("(") ||text.endsWith(")")|| text.endsWith(" ") || text.endsWith("-") )
return;
switch (textlength){
case 1:
etyEditText.setEditText(new StringBuilder(text).insert(text.length() - 1, "(").toString());
etyEditText.setSelection(etyEditText.getText().length());
break;
case 5:
etyEditText.setEditText(new StringBuilder(text).insert(text.length() - 1, ")").toString());
etyEditText.setSelection(etyEditText.getText().length());
break;
case 6:
etyEditText.setEditText(new StringBuilder(text).insert(text.length() - 1, " ").toString());
etyEditText.setSelection(etyEditText.getText().length());
break;
case 10:
etyEditText.setEditText(new StringBuilder(text).insert(text.length() - 1, "-").toString());
etyEditText.setSelection(etyEditText.getText().length());
break;
}
}
于 2018-12-03T11:19:23.037 回答
3
//(123) 456 7890 formate set
private int textlength = 0;
public class MyPhoneTextWatcher implements TextWatcher {
@Override
public void beforeTextChanged(CharSequence charSequence, int i, int i1, int i2) {
}
@Override
public void onTextChanged(CharSequence charSequence, int i, int i1, int i2) {
String text = etMobile.getText().toString();
textlength = etMobile.getText().length();
if (text.endsWith(" "))
return;
if (textlength == 1) {
if (!text.contains("(")) {
etMobile.setText(new StringBuilder(text).insert(text.length() - 1, "(").toString());
etMobile.setSelection(etMobile.getText().length());
}
} else if (textlength == 5) {
if (!text.contains(")")) {
etMobile.setText(new StringBuilder(text).insert(text.length() - 1, ")").toString());
etMobile.setSelection(etMobile.getText().length());
}
} else if (textlength == 6 || textlength == 10) {
etMobile.setText(new StringBuilder(text).insert(text.length() - 1, " ").toString());
etMobile.setSelection(etMobile.getText().length());
}
}
@Override
public void afterTextChanged(Editable editable) {
}
}
于 2017-03-10T12:19:02.647 回答
2
You can use a Regular Expression with pattern matching to extract number from a string.
String s="";
Pattern p = Pattern.compile("\\d+");
Matcher m = p.matcher("(1111)123-456-789"); //editText.getText().toString()
while (m.find()) {
s=s+m.group(0);
}
System.out.println("............"+s);
Output : ............1111123456789
于 2013-03-26T21:23:43.180 回答
2
如果您只对国际号码感兴趣，并且希望能够在输入中显示与国家/地区代码匹配的国家/地区的国旗，我为此编写了一个小型库：
https://github.com/tfcporciuncula/phonemoji
这是它的外观：
于 2020-08-20T10:34:38.073 回答
1
不用担心。我已经为你做了一个更好的解决方案。您可以在下面看到这个简单的应用程序链接。
private EditText mPasswordField;
public int textLength = 0;
@Override
protected void onCreate(@Nullable Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
mPasswordField = (EditText) findViewById(R.id.password_field);
mPasswordField.addTextChangedListener(this);
}
@Override
public void beforeTextChanged(CharSequence s, int start, int count, int after) {
}
@Override
public void onTextChanged(CharSequence s, int start, int before, int count) {
String text = mPasswordField.getText().toString();
textLength = mPasswordField.getText().length();
if (text.endsWith("-") || text.endsWith(" ") || text.endsWith(" "))
return;
if (textLength == 1) {
if (!text.contains("(")) {
mPasswordField.setText(new StringBuilder(text).insert(text.length() - 1, "(").toString());
mPasswordField.setSelection(mPasswordField.getText().length());
}
} else if (textLength == 5) {
if (!text.contains(")")) {
mPasswordField.setText(new StringBuilder(text).insert(text.length() - 1, ")").toString());
mPasswordField.setSelection(mPasswordField.getText().length());
}
} else if (textLength == 6) {
mPasswordField.setText(new StringBuilder(text).insert(text.length() - 1, " ").toString());
mPasswordField.setSelection(mPasswordField.getText().length());
} else if (textLength == 10) {
if (!text.contains("-")) {
mPasswordField.setText(new StringBuilder(text).insert(text.length() - 1, "-").toString());
mPasswordField.setSelection(mPasswordField.getText().length());
}
} else if (textLength == 15) {
if (text.contains("-")) {
mPasswordField.setText(new StringBuilder(text).insert(text.length() - 1, "-").toString());
mPasswordField.setSelection(mPasswordField.getText().length());
}
}else if (textLength == 18) {
if (text.contains("-")) {
mPasswordField.setText(new StringBuilder(text).insert(text.length() - 1, "-").toString());
mPasswordField.setSelection(mPasswordField.getText().length());
}
} else if (textLength == 20) {
Intent i = new Intent(MainActivity.this, Activity2.class);
startActivity(i);
}
}
@Override
public void afterTextChanged(Editable s) {
}
不：不要忘记在您的活动类中“实现 TextWatcher”。
链接：https ://drive.google.com/open?id=0B-yo9VvU7jyBMjJpT29xc2k5bnc
希望您对这个解决方案感到很酷。
于 2017-07-12T07:12:57.147 回答
1
您可以使用 spawns 在 Android 中格式化电话号码。此解决方案比其他解决方案更好，因为它不会更改输入文本。格式化仍然是纯视觉的。
implementation 'com.googlecode.libphonenumber:libphonenumber:7.0.4'
格式化程序类：
open class PhoneNumberFormatter : TransformationMethod {
private val mFormatter: AsYouTypeFormatter = PhoneNumberUtil.getInstance().getAsYouTypeFormatter(Locale.getDefault().country)
override fun getTransformation(source: CharSequence, view: View): CharSequence {
val formatted = format(source)
if (source is Spannable) {
setSpans(source, formatted)
return source
}
return formatted
}
override fun onFocusChanged(view: View?, sourceText: CharSequence?, focused: Boolean, direction: Int, previouslyFocusedRect: Rect?) = Unit
private fun setSpans(spannable: Spannable, formatted: CharSequence): CharSequence {
spannable.clearSpawns()
var charterIndex = 0
var formattedIndex = 0
var spawn = ""
val spawns: List<String> = spannable
.map {
spawn = ""
charterIndex = formatted.indexOf(it, formattedIndex)
if (charterIndex != -1){
spawn = formatted.substring(formattedIndex, charterIndex-1)
formattedIndex = charterIndex+1
}
spawn
}
spawns.forEachIndexed { index, sequence ->
spannable.setSpan(CharterSpan(sequence), index, index + 1, Spanned.SPAN_EXCLUSIVE_EXCLUSIVE)
}
return formatted
}
private fun Spannable.clearSpawns() =
this
.getSpans(0, this.length, CharterSpan::class.java)
.forEach { this.removeSpan(it) }
private fun format(spannable: CharSequence): String {
mFormatter.clear()
var formated = ""
for (i in 0 until spannable.length) {
formated = mFormatter.inputDigit(spannable[i])
}
return formated
}
private inner class CharterSpan(private val charters: String) : ReplacementSpan() {
var space = 0
override fun getSize(paint: Paint, text: CharSequence, start: Int, end: Int, fm: Paint.FontMetricsInt?): Int {
space = Math.round(paint.measureText(charters, 0, charters.length))
return Math.round(paint.measureText(text, start, end)) + space
}
override fun draw(canvas: Canvas, text: CharSequence, start: Int, end: Int, x: Float, top: Int, y: Int, bottom: Int, paint: Paint) {
space = Math.round(paint.measureText(charters, 0, charters.length))
canvas.drawText(text, start, end, x + space, y.toFloat(), paint)
canvas.drawText(charters, x, y.toFloat(), paint)
}
}
}
用法：
editText.transformationMethod = formatter
于 2019-03-27T13:52:05.943 回答
0
此代码适用于 (216) 555-5555
etphonenumber.addTextChangedListener(new TextWatcher()
{
@Override
public void onTextChanged(CharSequence s, int start, int before, int count)
{
// TODO Auto-generated method stub
}
@Override
public void beforeTextChanged(CharSequence s, int start, int count, int after)
{
// TODO Auto-generated method stub
}
@Override
public void afterTextChanged(Editable s)
{
String text = etphonenumber.getText().toString();
int textLength = etphonenumber.getText().length();
if (text.endsWith("-") || text.endsWith(" ") || text.endsWith(" "))
return;
if (textLength == 1) {
if (!text.contains("("))
{
etphonenumber.setText(new StringBuilder(text).insert(text.length() - 1, "(").toString());
etphonenumber.setSelection(etphonenumber.getText().length());
}
}
else if (textLength == 5)
{
if (!text.contains(")"))
{
etphonenumber.setText(new StringBuilder(text).insert(text.length() - 1, ")").toString());
etphonenumber.setSelection(etphonenumber.getText().length());
}
}
else if (textLength == 6)
{
etphonenumber.setText(new StringBuilder(text).insert(text.length() - 1, " ").toString());
etphonenumber.setSelection(etphonenumber.getText().length());
}
else if (textLength == 10)
{
if (!text.contains("-"))
{
etphonenumber.setText(new StringBuilder(text).insert(text.length() - 1, "-").toString());
etphonenumber.setSelection(etphonenumber.getText().length());
}
}
}
});
于 2021-03-12T18:21:38.477 回答
0
您只能接受使用 java 代码的数字和电话号码类型
EditText number1 = (EditText) layout.findViewById(R.id.edittext);
number1.setInputType(InputType.TYPE_CLASS_NUMBER|InputType.TYPE_CLASS_PHONE);
number1.setKeyListener(DigitsKeyListener.getInstance("0123456789”));
number1.setFilters(new InputFilter[] {new InputFilter.LengthFilter(14)}); // 14 is max digits
此代码将在读取输入后避免大量验证
于 2018-11-01T18:07:09.003 回答