php - 在 if/else 中使用 in_array 和日期的问题

Question

我正在试验 PHP 的date和in_array函数。

根据我在手册中阅读的内容，我无法理解为什么我的代码会返回 if 语句的 else 部分。如果date('D')返回Tue为什么不运行 if 部分？

<?php

date_default_timezone_set('UTC');

$weekdays = array("Mon", "Tue", "Wed", "Thur", "Fri", "Sat", "Sun");

$today = date('D');

if(in_array("Mon", "Tue", "Wed", "Thur", "Fri", $weekdays) == $today)
   {
         echo "It's" . " ";
         echo $today;
         echo " " . "Get out of bed and go to work";
    }else{
         echo "Do whatever you want becuase it's" . " ";
         echo $today;
};
?>

我尝试了各种方法并将if部分更改为此，但无济于事。

if(in_array(array("Mon", "Tue", "Wed", "Thur", "Fri"), $weekdays) == $today)

有人能告诉我语法有什么问题吗？

Answer 1

if(in_array($today, $weekdays))
   {
         echo "It's" . " ";
         echo $today;
         echo " " . "Get out of bed and go to work";
    }else{
         echo "Do whatever you want becuase it's" . " ";
         echo $current_day;
};

in_array手册

Answer 2

该in_array函数检查数组中是否存在值，返回 true 或 false。

如果您想知道是否$today是工作日，您需要执行以下操作：

$weekdays = array("Mon", "Tue", "Wed", "Thur", "Fri");
if(in_array($today, $weekdays)) {
   ...
}