我正在学习网络编程,并试图通过这个例子掌握套接字的基础知识。
import socket,sys
s = socket.socket(socket.AF_INET,socket.SOCK_DGRAM)
MAX = 65535
PORT = 1060
if sys.argv[1:] == ['server']:
s.bind(('127.0.0.1',PORT))
print 'Listening at ' , s.getsockname()
while True:
data,address = s.recvfrom(MAX)
print ' The address at ' , address , ' says ' , repr(data)
s.sendto('your data was %d bytes' % len(data),address)
elif sys.argv[1:] == ['client']:
print ' Address before sending ' ,s.getsockname()
s.sendto('This is the message',('127.0.0.1',PORT))
print ' Address after sending ' ,s.getsockname()
data,address = s.recvfrom(MAX)
print ' The server at ' , address , ' says ' , repr(data)
else:
print >> sys.stderr, 'usage: udp_local.py server | client '
但是,它抛出了一个异常,指出getsockname()给出的参数在第22行特别无效。据我所知,代码是正确的。这是异常
Traceback (most recent call last):
File "udp_local.py", line 23, in <module>
print ' Address before sending ' ,s.getsockname()
File "c:\Python27\lib\socket.py", line 224, in meth
return getattr(self._sock,name)(*args)
error: [Errno 10022] An invalid argument was supplied
使用 PyScripter 2.5.3.0 x86