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我通过 Spring security 保护了项目。我需要确定刚刚访问 JSP 的用户是否已经登录。我已经阅读了一些文章、帖子和文档，并尝试使用以下代码实现它：

<sec:authorize ifAnyGranted="ROLE_ANONYMOUS">
            USER NOT LOGGED IN
    <td><a href="<c:url value="/login"/>">Login</a></td>
</sec:authorize>
<sec:authorize ifNotGranted="ROLE_ANONYMOUS">       
            USER LOGGED IN
    <td><a href="<c:url value="/j_spring_security_logout"/>">Logout</a></td>
</sec:authorize>

尽管如此，我总是得到“用户登录”，我不知道为什么..这是我的安全上下文

<beans xmlns:security="http://www.springframework.org/schema/security"
   xmlns="http://www.springframework.org/schema/beans"
   xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
   xsi:schemaLocation="http://www.springframework.org/schema/beans
             http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
             http://www.springframework.org/schema/security
             http://www.springframework.org/schema/security/spring-security-3.1.xsd">

<security:http pattern="/resources/**" security="none"/>
<security:http pattern="/login*" security="none" auto-config="true"/>
<security:http pattern="/denied" security="none"/>

<security:http auto-config="true" access-denied-page="/denied" servlet-api-provision="false">
    <security:intercept-url pattern="/login*" access="IS_AUTHENTICATED_ANONYMOUSLY"/>
    <security:intercept-url pattern="/edit/**" access="ROLE_EDIT"/>
    <security:intercept-url pattern="/admin/**" access="ROLE_ADMIN"/>
    <security:intercept-url pattern="/**" access="ROLE_USER"/>
    <security:form-login login-page="/login"  authentication-failure-url="/denied"
                         default-target-url="/"/>
    <security:logout  logout-success-url="/login" />
</security:http>

<security:authentication-manager>
    <security:authentication-provider>
        <security:user-service>
            <security:user name="adam" password="adampassword" authorities="ROLE_USER"/>
            <security:user name="jane" password="janepassword" authorities="ROLE_USER, ROLE_ADMIN"/>
            <security:user name="sue" password="suepassword" authorities="ROLE_USER, ROLE_EDIT"/>
        </security:user-service>
    </security:authentication-provider>
</security:authentication-manager>

</beans>

我会很感激任何帮助:)

4

1 回答 1

2

如果任何人都可以访问页面，如您在安全上下文中设置的那样，您可以有条件地显示如下内容：

<sec:authorize var="loggedIn" access="isAuthenticated()"/>

然后使用相当标准的jstl可以：

<c:choose>
  <c:when test="${loggedIn}">
    <td><a href="<c:url value="/j_spring_security_logout"/>">Logout</a></td>

一点谷歌搜索告诉我ifnotgranted 已被弃用

于 2013-03-26T13:14:58.020 回答