python - 遍历 JSON 数组并对其进行排序

Question

我需要将 JSON 数组整理成层次结构，这里我的 JSON 文件从未排序，但遵循结构：

{
  "name":"Folder 2",
  "id":"zRDg",
  "parent":"OY00",
  "type":"folder"
},
{
  "name":"Folder 1",
  "id":"OY00",
  "type":"folder"
},
{
  "name":"Folder 3",
  "id":"ZDE1",
  "type":"folder"
},
{
  "name":"DX00025.jpg",
  "id":"9Xdd",
  "parent":"OY00",
  "type":"jpeg"
}

进入这个：

{
  "name":"Folder 1",
  "id":"OY00",
  "type":"folder",
  "children": [{
    "name":"Folder 2",
    "id":"zRDg",
    "type":"folder"
    },
    {
    "name":"DX00025.jpg",
    "id":"9Xdd",
    "type":"jpeg"
  }]
},
{
    "name":"Folder 3",
    "id":"ZDE1",
    "type":"folder"
}

我无法弄清楚，因为我是 python 新手，我的开始（错误）：

for index,item in result:
    if item['parent']:
        for item2 in result:
            if item2['id'] == item['parent']:
                item['children'] = item2
                brake 

这没关系，但问题是它不正确python，folder1/folder/folder3/ 不会为此工作，我需要一个递归函数

Answer 1

我对这种情况的解决方案是这样的：

data = INPUT_LIST

class Item:
    def __init__(self, _id, name, type, parent):
        self._id = _id
        self.name = name
        self.type = type
        self.parent = parent
        self.children = []

    def get_dict(self):
        return {
            'id': self._id,
            'name': self.name,
            'type': self.type,
            'children': [child.get_dict() for child in self.children]
        }


lookup = dict((item['id'], Item(item['id'], item['name'], item['type'], item['parent'] if 'parent' in item else None)) for item in data)

root = []

for _id, item in lookup.items():
    if not item.parent:
        root.append(item)
    else:
        lookup[item.parent].children.append(item)

dict_result = [item.get_dict() for item in root]