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我的应用程序在 Sony Experia (2.3) 上成功运行,但在三星 Galaxy Tab (4.1) 上运行时出现异常。我的问题是,在录制视频并将其转换为 base64 字符串后,在将其解析为肥皂时出现错误。

这是我捕获视频的代码(传递意图):

Intent videoIntent = new Intent(MediaStore.ACTION_VIDEO_CAPTURE);

videoIntent.putExtra(MediaStore.EXTRA_DURATION_LIMIT, 10);

videoIntent.putExtra(MediaStore.EXTRA_VIDEO_QUALITY, 0);

startActivityForResult(videoIntent, ACTION_TAKE_VIDEO);

关于活动结果方法:

public void onActivityResult(int requestCode, int resultCode, Intent data) {
super.onActivityResult(requestCode, resultCode, data);

if ((requestCode == ACTION_TAKE_VIDEO && resultCode == RESULT_OK)) {
System.out.println("capturing video");
Uri selectedImage = data.getData();
String videoPath = getRealPathFromURI(selectedImage);

Bitmap bm = ThumbnailUtils.createVideoThumbnail(videoPath, MediaStore.Images.Thumbnails.MINI_KIND);
videoview.setImageBitmap(bm);
System.out.println("videobitmap=="+bm);

bytes[]datas = null;
String dataPath = videoPath;
InputStream is = null;

try {
is = new FileInputStream(dataPath);
datas = readBytes(is);
} catch (FileNotFoundException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}

String encodedImage = Base64.encodeToString(datas, Base64.DEFAULT);
isInternetPresent = cd.isConnectingToInternet();

if (isInternetPresent) {
new BufferingVideo().execute(encodedImage);
} else {
Toast.makeText(getApplicationContext(), "Sorry, we couldn't connect to server, please check your 
internet connection", Toast.LENGTH_LONG).show();
}
}
}

public byte[] readBytes(InputStream inputStream) throws IOException {
ByteArrayOutputStream byteBuffer = new ByteArrayOutputStream();
int bufferSize = 1024;
byte[] buffer = new byte[bufferSize];
int len = 0;

while ((len = inputStream.read(buffer)) != -1) {
byteBuffer.write(buffer, 0, len);
}

return byteBuffer.toByteArray();
}

public String getRealPathFromURI(Uri contentUri) {
String[] proj = { MediaStore.Images.Media.DATA };
Cursor cursor = managedQuery(contentUri, proj, null, null, null);
int column_index = cursor.getColumnIndexOrThrow(MediaStore.Images.Media.DATA);
cursor.moveToFirst();
return cursor.getString(column_index);
}

现在将 base64 字符串传递给 Webservice:

protected String doInBackground(String... params) {
String st = params[0];
System.out.println("st==== " + st);

SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME4);

System.err.println("Request  = " + request);
request.addProperty("VideoBuffer", st);
request.addProperty("VideoName", "VideoCar");
request.addProperty("ModuleName", modulename);
}

我的 Logcat 错误是:

致命异常:AsyncTask #5
java.lang.RuntimeException:执行 doInBackground() 时发生错误
  在 android.os.AsyncTask$3.done(AsyncTask.java:299)
  在 java.util.concurrent.FutureTask$Sync.innerSetException(FutureTask.java:273)
  在 java.util.concurrent.FutureTask.setException(FutureTask.java:124)
  在 java.util.concurrent.FutureTask$Sync.innerRun(FutureTask.java:307)
  在 java.util.concurrent.FutureTask.run(FutureTask.java:137)
  在 java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1076)
  在 java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:569)
  在 java.lang.Thread.run(Thread.java:856)
  引起:java.lang.OutOfMemoryError
  在 java.lang.AbstractStringBuilder.enlargeBuffer(AbstractStringBuilder.java:94)
  在 java.lang.AbstractStringBuilder.append0(AbstractStringBuilder.java:145)
  在 java.lang.StringBuffer.append(StringBuffer.java:219)
  在 org.ksoap2.serialization.SoapObject.toString(SoapObject.java:456)
  在 java.lang.StringBuilder.append(StringBuilder.java:202)
  在 web.org.HouseRentInsertAds$BufferingVideo.doInBackground(HouseRentInsertAds.java:897)
  在 web.org.HouseRentInsertAds$BufferingVideo.doInBackground(HouseRentInsertAds.java:1)
  在 android.os.AsyncTask$2.call(AsyncTask.java:287)
  在 java.util.concurrent.FutureTask$Sync.innerRun(FutureTask.java:305)

请给我一个解决方案。

4

1 回答 1

1

在将整个图像发送到服务器之前,您必须压缩图像。

公开

String String_Image; 
Bitmap bitmap;

这里解码图像并将压缩图像发送到服务器的过程

File image_file = new File(path);
decodeFile(image_file);         
ByteArrayOutputStream bao = new ByteArrayOutputStream();
bitmap.compress(Bitmap.CompressFormat.JPEG, 90, bao);
byte[] ba = bao.toByteArray();
String_Image = Base64.encodeBytes(ba);

decodeFile()函数将解码您的文件。

private Bitmap decodeFile(File f)
    {
        try
        {
            // Decodes image size
            BitmapFactory.Options o = new BitmapFactory.Options();
            o.inJustDecodeBounds = true;
            BitmapFactory.decodeStream(new FileInputStream(f), null, o);

            // The new size to scale to
            final int REQUIRED_SIZE = 70;

            // Finds the correct scale value which should be the power of 2.
            int scale = 1;
            while (o.outWidth / scale / 2 >= REQUIRED_SIZE
                    && o.outHeight / scale / 2 >= REQUIRED_SIZE)
                scale *= 2;

            // Decodes with inSampleSize
            BitmapFactory.Options o2 = new BitmapFactory.Options();
            o2.inSampleSize = scale;
            bitmap = BitmapFactory.decodeStream(new FileInputStream(f), null,
                    o2);
            return bitmap;
        } catch (FileNotFoundException e)
        {
        }
        return null;
    }

发送String_Image到服务器。

此代码适用于图像,但同样适用于其他代码。尝试进行一些更改。

希望它会奏效。

于 2013-03-26T09:58:30.553 回答