ios - UITapGestureRecognizer - 让它在触地时工作，而不是触地？

Question

我使用点击事件对时间非常敏感，所以我很好奇是否可以在用户简单地触摸时激活 UITapGestureRecognizer，而不是要求他们也触摸？

Answer 1

使用 UILongPressGestureRecognizer 并将其设置minimumPressDuration为 0。它会在状态期间起到触地的作用UIGestureRecognizerStateBegan。

对于斯威夫特 4+

func setupTap() {
    let touchDown = UILongPressGestureRecognizer(target:self, action: #selector(didTouchDown))
    touchDown.minimumPressDuration = 0
    view.addGestureRecognizer(touchDown)
}

@objc func didTouchDown(gesture: UILongPressGestureRecognizer) {
    if gesture.state == .began {
        doSomething()
    }
}

对于 Objective-C

-(void)setupLongPress
{
   self.longPress = [[UILongPressGestureRecognizer alloc] initWithTarget:self action:@selector(didLongPress:)];
   self.longPress.minimumPressDuration = 0;
   [self.view addGestureRecognizer:self.longPress];
}

-(void)didLongPress:(UILongPressGestureRecognizer *)gesture
{
   if (gesture.state == UIGestureRecognizerStateBegan){
      [self doSomething];
   }
}

Answer 2

创建您的自定义 TouchDownGestureRecognizer 子类并在 touchesBegan 中实现手势：

TouchDownGestureRecognizer.h

#import <UIKit/UIKit.h>

@interface TouchDownGestureRecognizer : UIGestureRecognizer

@end

TouchDownGestureRecognizer.m

#import "TouchDownGestureRecognizer.h"
#import <UIKit/UIGestureRecognizerSubclass.h>

@implementation TouchDownGestureRecognizer
-(void)touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event{
    if (self.state == UIGestureRecognizerStatePossible) {
        self.state = UIGestureRecognizerStateRecognized;
    }
}

-(void)touchesMoved:(NSSet *)touches withEvent:(UIEvent *)event{
    self.state = UIGestureRecognizerStateFailed;
}

-(void)touchesEnded:(NSSet *)touches withEvent:(UIEvent *)event{
    self.state = UIGestureRecognizerStateFailed;
}


@end

执行：

#import "TouchDownGestureRecognizer.h"
    TouchDownGestureRecognizer *touchDown = [[TouchDownGestureRecognizer alloc] initWithTarget:self action:@selector(handleTouchDown:)];
    [yourView addGestureRecognizer:touchDown];

-(void)handleTouchDown:(TouchDownGestureRecognizer *)touchDown{
    NSLog(@"Down");
}

---

快速实现：

import UIKit
import UIKit.UIGestureRecognizerSubclass

class TouchDownGestureRecognizer: UIGestureRecognizer
{
    override func touchesBegan(touches: Set<UITouch>, withEvent event: UIEvent)
    {
        if self.state == .Possible
        {
            self.state = .Recognized
        }
    }

    override func touchesMoved(touches: Set<UITouch>, withEvent event: UIEvent)
    {
        self.state = .Failed
    }

    override func touchesEnded(touches: Set<UITouch>, withEvent event: UIEvent)
    {
        self.state = .Failed
    }
}

---

这是 2017 年要粘贴的 Swift 语法：

import UIKit.UIGestureRecognizerSubclass

class SingleTouchDownGestureRecognizer: UIGestureRecognizer {
    override func touchesBegan(_ touches: Set<UITouch>, with event: UIEvent) {
        if self.state == .possible {
            self.state = .recognized
        }
    }
    override func touchesMoved(_ touches: Set<UITouch>, with event: UIEvent) {
        self.state = .failed
    }
    override func touchesEnded(_ touches: Set<UITouch>, with event: UIEvent) {
        self.state = .failed
    }
}

请注意，这是UITap. 所以在代码中......

func add(tap v:UIView, _ action:Selector) {
    let t = UITapGestureRecognizer(target: self, action: action)
    v.addGestureRecognizer(t)
}

你可以安全地换成....

func add(hairtriggerTap v:UIView, _ action:Selector) {
    let t = SingleTouchDownGestureRecognizer(target: self, action: action)
    v.addGestureRecognizer(t)
}

测试表明它不会被多次调用。它可以作为替代品使用；你可以在两个电话之间交换。

Answer 3

Swift（没有子类化）

这是一个类似于Rob Caraway 的 Objective-C 答案的 Swift 版本。

这个想法是使用minimumPressDuration设置为零的长按手势识别器，而不是使用轻击手势识别器。这是因为长按手势识别器会报告触摸开始事件，而轻击手势则不会。

import UIKit
class ViewController: UIViewController {

    @IBOutlet weak var myView: UIView!

    override func viewDidLoad() {
        super.viewDidLoad()

        // Add "long" press gesture recognizer
        let tap = UILongPressGestureRecognizer(target: self, action: #selector(tapHandler))
        tap.minimumPressDuration = 0
        myView.addGestureRecognizer(tap)
    }

    // called by gesture recognizer
    @objc func tapHandler(gesture: UITapGestureRecognizer) {

        // handle touch down and touch up events separately
        if gesture.state == .began {
            // do something...
            print("tap down")
        } else if gesture.state == .ended { // optional for touch up event catching
            // do something else...
            print("tap up")
        }
    }
}

Answer 4

我需要能够让我的视图有一个头发触发器，以便一旦它被点击它就会响应。使用@LESANG 答案和使用@RobCaraway 答案都有效。我在两个答案中遇到的问题是我失去了识别滑动的能力。滑动时我需要旋转视图，但只要我的手指触摸视图，就只能识别出水龙头。tapRecognizer 太敏感了，无法区分点击和滑动。

这是我根据@LESANG 的答案结合这个答案和这个答案得出的。

我在每个事件中发表了 6 条评论。

import UIKit.UIGestureRecognizerSubclass

class SingleTouchDownGestureRecognizer: UIGestureRecognizer {


    var wasSwiped = false

    override func touchesBegan(_ touches: Set<UITouch>, with event: UIEvent) {

        guard let view = self.view else { return }
        guard let touches = event.touches(for: view) else { return } // 1. compare that event in touchesBegan has touches for the view that is the same as the view to which your gesture recognizer was assigned

        if touches.first != nil {
            print("Finger touched!") // 2. this is when the user's finger first touches the view and is at locationA
            wasSwiped = false // 3. it would seem that I didn't have to set this to false because the property was already set to false but for some reason when I didn't add this it wasn't responding correctly. Basically set this to false
        }
    }

    override func touchesMoved(_ touches: Set<UITouch>, with event: UIEvent) {

        guard let touch = touches.first else { return }

        let newLocation = touch.location(in: self.view)
        let previousLocation = touch.previousLocation(in: self.view)

        if (newLocation.x > previousLocation.x) || (newLocation.x < previousLocation.x) {
            print("finger touch went right or left") // 4. when the user's finger first touches it's at locationA. If the the user moves their finger to either the left or the right then the finger is no longer at locationA. That means it moved which means a swipe occurred so set the "wasSwiped" property to true

            wasSwiped = true // 5. set the property to true because the user moved their finger
        }
    }

    override func touchesEnded(_ touches: Set<UITouch>, with event: UIEvent) {
        print("finger is no longer touching.") // 6. the user has lifted their finger off of the view. If "wasSwiped" is true then ".fail" but if it wasn't swiped then ".recognize"

        if wasSwiped {
            self.state = .failed
        } else {
            self.state = .recognized
        }
    }
}

并使用它，以便使用它的视图获得头发触发响应和左右滑动手势：

let tapGesture = SingleTouchDownGestureRecognizer(target: self, action: #selector(viewWasTapped(_:)))
myView.addGestureRecognizer(tapGesture)

let rightGesture = UISwipeGestureRecognizer(target: self, action: #selector(respondToSwipeGesture(recognizer:)))
rightGesture.direction = .right
myView.addGestureRecognizer(rightGesture)

let leftGesture = UISwipeGestureRecognizer(target: self, action: #selector(respondToSwipeGesture(recognizer:)))
leftGesture.direction = .left
myView.addGestureRecognizer(leftGesture)

Answer 5

这是另一种解决方案。创建 UIControl 的子类。即使在 Storyboard 中，您也可以像 UIView 一样使用它，因为 UIControl 是 UIView 的子类。

class TouchHandlingView: UIControl {
}

并添加目标：

@IBOutlet weak var mainView: TouchHandlingView!
...

mainView.addTarget(self, action: "startAction:", forControlEvents: .TouchDown)
...

然后指定的action会像UIButton一样被调用：

func startAction(sender: AnyObject) {
    print("start")
}