我正在尝试做到这一点,所以当我单击跨度图标时,它会将 article_id 发送到我的 php sql 页面,该页面会删除我的文章,我正在使用 jQuery Ajax 发送 id,id 在 jQuery 端发送正常但之后http post请求已完成,我的表格行仍然存在,任何人都可以查看我的代码是否有问题,在此先感谢!
<?php
$sql_categories = "SELECT art_id, art_title, art_company, art_cat_id, art_sta_id, art_date, art_rating, art_price, cat_id, cat_name, sta_id, sta_name
FROM app_articles LEFT JOIN app_categories
ON app_articles.art_cat_id = app_categories.cat_id
LEFT JOIN app_status
ON app_articles.art_sta_id = app_status.sta_id
ORDER BY art_order ASC";
if($result = query($sql_categories)){
$list = array();
while($data = mysqli_fetch_assoc($result)){
array_push($list, $data);
}
foreach($list as $i => $row){
?>
<div class="row" id="page_<?php echo $row['art_id']; ?>">
<div class="column one">
<span class="icon-small move"></span>
<a href="edit-article.php?art_id=<?php echo $row['art_id']; ?>"><span class="icon-small edit"></span></a>
<span id="<?php echo $row['art_id']; ?>" class="icon-small trash"></span>
</div>
<div class="column two"><p><?php echo $row['art_title']; ?></p></div>
<div class="column two"><p><?php echo $row['art_company']; ?></p></div>
<div class="column two"><p><?php echo $row['cat_name']; ?></p></div>
<div class="column one"><p><?php echo $row['art_date']; ?></p></div>
<div class="column one"><p><?php echo $row['art_rating']; ?></p></div>
<div class="column one"><p><?php echo $row['art_price']; ?></p></div>
<div class="column one"><p><?php echo $row['sta_name']; ?></p></div>
<div class="column one"><a href=""><span class="icon-small star"></span></a></div>
</div>
<?php
}
}
else {
echo "FAIL";
}
?>
jQuery
$(document).ready(function(){
$(".trash").click(function(){
var del_id = $(this).attr('id');
$.ajax({
type:'POST',
url:'ajax-delete.php',
data: 'delete_id='+del_id,
success:function(data) {
if(data) {
}
else {
}
}
});
});
});
PHP mySQL Statement
if(isset($_POST['delete_id'])) {
$sql_articles = "DELETE FROM app_articles WHERE art_id = ".$_POST['delete_id'];
if(query($sql_articles)) {
echo "YES";
}
else {
echo "NO";
}
}
else {
echo "FAIL";
}
?>