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我无法对从 Excel 表中提取的现有日期时间进行更改（增加秒数）。

Code:
import xlrd
import xlwt
from datetime import datetime, timedelta
wb = xlrd.open_workbook('sample.xls')
wb2 = xlrd.open_workbook('sample2.xls')
# Load XLRD Excel Reader

sheetname = wb.sheet_names() #Read for XCL Sheet names
sh1 = wb.sheet_by_index(0) #Login
sheetname2 = wb2.sheet_names() #Read for XCL Sheet names
sh2 = wb2.sheet_by_index(0) #Login

def readRows():
    #a = datetime.time(10, 23)
    #print a
    for rownum in range(sh1.nrows):
        rows = sh1.row_values(rownum)
        for rownum2 in range(sh2.nrows):
            rows2 = sh2.row_values(rownum2)
            date = rows[0]
            date2 = rows2[0]
            print xlrd.xldate_as_tuple(date,0)
            print xlrd.xldate_as_tuple(date2,0)
            #date2 = rows2[0]
            if date == date2 :
                #print 'found'
                time = rows[2]
                time2 = rows2[2]
                if time == time2 :
                    print 'time matched'
                    #remaining code
                elif(time<time2)&&(time+datetime.timedelta(0,15)>time2)):
                    print 'less'
                    ti=xlrd.xldate_as_tuple(time,0)
                    ti2=xlrd.xldate_as_tuple(time2,0)
                    print ti,ti2 # shows (2013,11,11,10,42,36) 
                    print a.time #not working
                    ti+=datetime.timedelta(seconds=3) #not working
                    ti2+=2 #not working
                    print ti,ti2
                    print time
                    time=datetime.datetime (xlrd.xldate_as_tuple(time,0)) + datetime.timedelta(0,1) #not working
                    time2 = xlrd.xldate_as_tuple(datetime.datetime(time2),0)+ datetime.timedelta(0,1) #not working
                    print (xlrd.xldate_as_tuple(time+timedelta(seconds=3),0)),(xlrd.xldate_as_tuple(time2+timedelta(seconds=3),0)) #not working
                elif (time > time2) & (time+datetime.timedelta(0,15) > time2)) :
                    print 'more'
                    print time,time2
print readRows()
input('enter to exit:')

我有两个日志文件。一个记录每 15 秒，另一个记录可变时间。因此，我需要将第二个日志的最接近值映射到第一个日志中的时间，因为我无法更改从 excel 表中提取的时间，但时间显示正确并进行了正确比较。

4

1 回答 1

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您可能需要更改 xldate_as_tuple 返回的元组的顺序或将月份更改为从零开始而不是从零开始......但基本上，一旦您将日期分成其部分，只需从中创建一个日期时间对象并添加时间差...

>>> year,month,day,hour,second = 2002,10,15,22,23  #oct 15 2002 @ 10.23pm
>>> d1 = datetime.datetime(year,month,day,hour,second)
>>> num_seconds = 3600 #one hour
>>> time_delt = datetime.timedelta(seconds=num_seconds)
>>> print d1+time_delt
2002-10-15 23:23:00
>>> #notice it is an hour later!

python 文档非常有帮助

http://docs.python.org/2/library/datetime.html#datetime.timedelta

http://docs.python.org/2/library/datetime.html#module-datetime

于 2013-03-25T23:26:50.620 回答