symfony - Dynamic service id in an argument in symfony2?

Question

Is it possible to set the service id in an argument dynamically (e.g. like a class name which could be set via parameter) in Symfony 2 (xml configs)?

The following does not work

<service id="myservice" class="myservice.php">
    <argument type="service" id="%dynamic_service_name%" />
</service>

<service id="service1" class="foobar\service1" />
<service id="service2" class="foobar\service1" />

the idea is to set the param %dynamic_service_name% dynamically to "service1" or "service2", so the needed instance/object is passed to myservice-class, e.g. in the Extension::load() via $container->setParameter('dynamic_service_name','service1');

Thanks a lot

score 16 · Accepted Answer

You can use CompilerPass:

class DynamicServiceCompilerPass implements CompilerPassInterface
{
    public function process(ContainerBuilder $container)
    {
        $container->getDefinition('myservice')
            ->setArguments(array(new Reference($container->getParameter('dynamic_service_name'))));
    }
}

and add it to your Bundle class:

public function build(ContainerBuilder $container)
{
    parent::build($container);

    $container->addCompilerPass(new DynamicServiceCompilerPass());
}

FOLLOW UP:

Since Symfony 2.4 you can use Expression Language like this:

<services>
    <service id="myservice" class="My\Service">
        <argument type="expression">service(container.hasParameter('dynamic_service_name') ? parameter('dynamic_service_name') : 'default_service_name')</argument>
    </service>
</services>

score 2 · Accepted Answer

您可以使用函数将参数读入服务定义中，并使用该parameter()函数创建服务service()。所以你可以创建一个动态服务

在你的parameters.yml

  parameters:
      dynamic_service_name:  mydynamicservice

在你的 services.yml

  myservice:
        class: My\Service
        arguments:['@=service(parameter("dynamic_service_name"))']

score 1 · Accepted Answer

直接来自 symfony2 文档 ;)

<!-- app/config/config.xml -->
<parameters>
    <parameter key="my_mailer.class">Acme\HelloBundle\Mailer</parameter>
    <parameter key="my_mailer.transport">sendmail</parameter>
</parameters>

<services>
    <service id="my_mailer" class="%my_mailer.class%">
        <argument>%my_mailer.transport%</argument>
    </service>
</services>

这就是你所追求的吗？

http://symfony.com/doc/current/book/service_container.html#service-parameters

编辑：

这是我的一项服务，使用参数。但是，它在 YAML 中。这工作得很好。如您所见，它在参数中使用类名和类的命名空间。

parameters:
    seer_ukd_wright_gallery.gallery_helper.class: SeerUK\DWright\GalleryBundle\DependencyInjection\GalleryHelper

services:
    seer_ukd_wright_gallery.gallery_helper:
        class: %seer_ukd_wright_gallery.gallery_helper.class%
        arguments:
            em: "@doctrine.orm.entity_manager"

score 0 · Accepted Answer

这大致就是使用容器本身作为工厂的方式。然后，您可以将“dynamic_service_name”定义为 service1 或 service2，它将加载到该服务中。（工厂的 XML 在 2.6 中略有不同，但应该仍然可以正常工作）

<service id="service1" class="foobar\service1" />
<service id="service2" class="foobar\service1" />

<service id="some.service" class="foobar\service1"
             factory-service="service_container"
             factory-method="get">
        <argument>%dynamic_service_name%</argument>
    </service>

<service id="myservice" class="myservice.php">
    <argument type="service" id="some.service" />
</service>

score -1 · Accepted Answer

添加到彼得福克斯的答案，这是 YAML 中的等价物：

some.service:
    class: Foobar\Service1
    factory_service: service_container
    factory_method: get
    arguments:
        - %dynamic_service_name%
myservice:
    class: MyService
    arguments:
        - @some.service

在如何指定两种服务的类方面存在两个小的差异。我不熟悉将文件名用作类，foobar\service1也不符合 PSR，所以我替换了这些。

symfony - Dynamic service id in an argument in symfony2?

5 回答 5

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