我正在开发一个 Android 应用程序,我需要发送一条消息以一次接收多个模拟器。但问题是只有一个模拟器正在接收消息。这是我的代码。
公共类 SMS 扩展 Activity {
/** Called when the activity is first created. */ @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); btnSendSMS = (Button) findViewById(R.id.btn_SendSms); txtPhoneNo = (EditText) findViewById(R.id.edittext_PhoneNumber); txtMessage = (EditText) findViewById(R.id.edittext_MessageBody); btnSendSMS.setOnClickListener(new View.OnClickListener() { public void onClick(View v) { String message = txtMessage.getText().toString(); String phoneNo = txtPhoneNo.getText().toString(); StringTokenizer st=new StringTokenizer(phoneNo,","); while (st.hasMoreElements()) { String tempMobileNumber = (String)st.nextElement(); if(tempMobileNumber.length()>0 && message.trim().length()>0) { sendSMS(tempMobileNumber, message); } else { Toast.makeText(getBaseContext(), "Please enter both phone number and message.", Toast.LENGTH_SHORT).show(); } } } }); } private void sendSMS(String phoneNumber, String message) { String SENT = "SMS_SENT"; String DELIVERED = "SMS_DELIVERED"; PendingIntent sentPI = PendingIntent.getBroadcast(this, 0, new Intent(SENT), 0); PendingIntent deliveredPI = PendingIntent.getBroadcast(this, 0, new Intent(DELIVERED), 0); //---when the SMS has been sent--- registerReceiver(new BroadcastReceiver() { @Override public void onReceive(Context arg0, Intent arg1) { switch (getResultCode()) { case Activity.RESULT_OK: Toast.makeText(getBaseContext(), "SMS sent", Toast.LENGTH_SHORT).show(); break; case SmsManager.RESULT_ERROR_GENERIC_FAILURE: Toast.makeText(getBaseContext(), "Generic failure", Toast.LENGTH_SHORT).show(); break; case SmsManager.RESULT_ERROR_NO_SERVICE: Toast.makeText(getBaseContext(), "No service", Toast.LENGTH_SHORT).show(); break; case SmsManager.RESULT_ERROR_NULL_PDU: Toast.makeText(getBaseContext(), "Null PDU", Toast.LENGTH_SHORT).show(); break; case SmsManager.RESULT_ERROR_RADIO_OFF: Toast.makeText(getBaseContext(), "Radio off", Toast.LENGTH_SHORT).show(); break; } } } , new IntentFilter(SENT)); SmsManager sms = SmsManager.getDefault(); sms.sendTextMessage(phoneNumber, null, message, sentPI, deliveredPI); } }
问问题
237 次
2 回答
0
要将 SMS 消息发送到在同一台机器上运行的另一个模拟器实例,请启动 SMS 应用程序。将目标模拟器实例的控制台端口号(例如:5555)指定为 SMS 地址。
请注意,此答案基于:Linuxtopia指南。
于 2013-03-25T12:09:06.853 回答
0
您可以创建模拟器 id 或编号的数组,然后将sendTextMessage放入执行循环的数组中。或者您可以拥有允许用户将电话号码或模拟器号码插入列表的用户界面,过程与上述相同!!!请注意,sendTextMessage的第一个参数是您要向其发送短信的“电话号码”,只需将其替换为您的要求,每次循环迭代
于 2013-03-25T13:34:10.363 回答