2

我不明白为什么它不起作用..

这是我的课

public class Article : Screen
{
    public string Code { get; set; }
    public string Description{ get; set; }
    public decimal Cost{ get; set; }
    public decimal Price{ get; set; }
}

这是 DataGrid 的 XAML 代码:

    <DataGrid Height="211" HorizontalAlignment="Left" 
        Margin="12,31,0,0" VerticalAlignment="Top" Width="521" 
        AutoGenerateColumns="False" ItemsSource="{Binding List}">
        <DataGrid.Columns>
            <DataGridTextColumn Binding="{Binding Path=Code}" Header="Code" />
            <DataGridTextColumn Binding="{Binding Path=Description}" Header="Description" />
            <DataGridTextColumn Binding="{Binding Path=Cost}" Header="Cost" />
            <DataGridTextColumn Binding="{Binding Path=Price}" Header="Price" />
        </DataGrid.Columns>
    </DataGrid>
    <Button Content="Button" Height="39" HorizontalAlignment="Left" 
            Margin="223,262,0,0" VerticalAlignment="Top" Width="110"
            x:Name="AllArticles"/>

这是我的视图模型

[Export(typeof(IShell))]
public class ArtsViewModel : Screen
{
    public List<Article> List = new List<Article>();

    public void AllArticles()
    {
        Recover recover = new Recover();  //a model called Recover
        List = recover.Import().Articles; //return a List of Article
        NotifyOfPropertyChange("List");
    }    
}

为什么数据网格不起作用?

4

4 回答 4

8

要在Caliburn.Micro中启用绑定约定,通常x:Name 在 XAML 中使用该属性。如果您不是将List属性显式绑定到ItemsSource您的 ,而是DataGrid使用如下命名约定:

<DataGrid x:Name="List" Height="211" HorizontalAlignment="Left" 
    Margin="12,31,0,0" VerticalAlignment="Top" Width="521" 
    AutoGenerateColumns="False">

我相信后续绑定应该可以按需要工作。

哦,你还需要创建List一个属性而不是一个字段:

public List<Article> List { get; private set; }

如果您想确保对 的修改List正确反映在您的数据网格中,您还应该使您的List属性IObservableCollection带有支持字段:

private IObservableCollection<Article> _list;
public IObservableCollection<Article> List { 
    get { return _list; }
    set {
        _list = value;
        NotifyOfPropertyChange(() => List);
    }
}
于 2013-03-24T17:27:02.957 回答
1

a) 您是否设置了 DataContext?

b)尝试“Binding =“{Binding Code}”(没有路径=),对我来说很好。

于 2013-03-24T17:02:47.770 回答
0

对于我的 UWP 应用,我发现 x:Name 约定不起作用,我需要使用可绑定集合并直接绑定到 ItemsSource。然后我使用 Path=PropertyName 来指定列。

XAML:

<controls:DataGrid Grid.Row="3" Grid.Column="1" Grid.ColumnSpan="3"  ItemsSource="{Binding RawCSVData}" AutoGenerateColumns="false">
        <controls:DataGrid.Columns>
            <controls:DataGridTextColumn Header="Time" Binding="{Binding Path=Time}"/>
            <controls:DataGridTextColumn Header="Signal" Binding="{Binding Path=Signal}"/>
            <controls:DataGridTextColumn Header="Response" Binding="{Binding Path=Response}"/>

        </controls:DataGrid.Columns>
    </controls:DataGrid>

CSVData.cs:

public class CSVData: Screen
{
    public double Time { get; set; }
    public double Signal { get; set; }
    public double Response { get; set; }
}

ViewModel.cs 片段:

public BindableCollection<CSVData> RawCSVData { get; set; }
于 2018-08-24T17:02:34.677 回答
-2
     private void _bookeditpage_ConfirmBook(Book _book, bool _isnewone) 
     {
        if (_isnewone)
        {
            Books.Add(_book);
        }
        else
        {
            //doesn't refresh datagrid
            SelectedBook = _book;
            //

            //works fine :)

            SelectedBook.BookName = _book.BookName;
            SelectedBook.IsPrenum=_book.IsPrenum;
            SelectedBook.Publisher=_book.Publisher;

           //
        }
    }
于 2015-08-03T10:48:37.253 回答