2

我正在尝试将变量传递给视图，这很奇怪，因为命名和目录结构是正确的。以下是我的控制器中的功能：

public function validate_apply_link(){
        App::uses('CakeEmail', 'Network/Email');

        $this->layout = 'blank';

        $listings = $this->CareersAndJob->query("
            SELECT l.sid, l.title, lp.value, u.CompanyName, u.WebSite
            FROM listings l
            LEFT JOIN listings_properties lp
            ON lp.object_sid = l.sid
            LEFT JOIN users u
            ON u.sid = l.user_sid
            WHERE l.active = 1
            AND lp.add_parameter = 2
            AND l.JobGateSenderReference IS NULL
            AND u.CompanyName != 'AECOM'
            ORDER BY u.CompanyName ASC
            LIMIT 5
            ");

        $doc = new DOMDocument();
        ob_start();
        $listing_count = count($listings);
        echo nl2br("Checking $listing_count active jobs...\n\n");
        $i=0;
        foreach($listings as $listing){

            $sid = $listing['l']['sid'];
            $url = $listing['lp']['value'];
            $company_name = $listing['u']['CompanyName'];
            $title = htmlspecialchars($listing['l']['title']);

            $length = strpos($title, "-");
            if($length != 0){
                $title = substr($title, 0, $length-1);
            }
            $title = substr($title, 0, $length-1);
            $title = substr($title, 0, 10);
            $data = $this->curl($url);

            $check_pdf = strpos($data['info']['content_type'], "pdf");
            if($check_pdf != false){
                $outputs['data'][$i]['url'] = $url;
                $outputs['data'][$i]['sid'] = $sid;
                $outputs['data'][$i]['title'] = $title;
                $outputs['data'][$i]['company_name'] = $company_name;
                $outputs['data'][$i]['our_link'] = "http://careersandjobs.com.au/display-job/{$sid}";
                $outputs['data'][$i]['content_type'] = $data['info']['content_type'];

                $outputs['data'][$i]['data_type'] = 'pdf';

                $i++;
                continue;
            }

            @$doc->loadHTML($data['results']);
            $html = $doc->saveHTML();
            $xpath = new DOMXpath($doc);

            $body = $doc->getElementsByTagName('body')->item(0);

            $parsed_url = parse_url($url);

            switch($parsed_url['host']){
                case "www.michaelpage.com.au":
                    parse_str($url);
                    $exist = $xpath->query("//*[contains(@value,'{$ref}')]");

                break;
                case "https://vacancies.mackay.qld.gov.au":
                    parse_str($url);
                    $exist = $xpath->query("//*[contains(@value,'{$title}')]");
                break;
                default:
                    $exist = $xpath->query("//*[contains(text(),'{$title}')]");
                break;
            }

            if($exist->length == 0){

                if(strpos($url, '#') == false){

                $outputs['data'][$i]['url'] = $url;
                $outputs['data'][$i]['sid'] = $sid;
                $outputs['data'][$i]['title'] = $title;
                $outputs['data'][$i]['company_name'] = $company_name;
                $outputs['data'][$i]['our_link'] = "http://careersandjobs.com.au/display-job/{$sid}";
                $outputs['data'][$i]['content_type'] = $data['info']['content_type'];

                $response_code = $this->http_response_codes($data['info']['http_code']);
                $outputs['data'][$i]['response_code'] = $response_code;

                $outputs['data'][$i]['data_type'] = 'title_not_found';


                }else{

                    $outputs['data'][$i]['data_type'] = 'no_iframe';
                }

                $i++;
            }

            flush();
            ob_flush();

        }

        $this->set(compact('outputs'));

    }

我可以pr对视图中的outputs变量进行操作，但这会输出到，NULL但是当我删除控制器函数内的整组代码并通过它传递一个测试变量时，它可以工作。

我不知道的功能有问题吗？

顺便说一下上面的函数没有发现错误

app/Controller/CareersAndJobsController.php (line 1048)
array(
    'data' => array(
        (int) 0 => array(
            'url' => 'http://bawbawshire.currentjobs.com.au/cvbuilder/apply+for+this+job/no/1225055',
            'sid' => '3649',
            'title' => 'Graduate P',
            'company_name' => 'Baw Baw Shire Council',
            'our_link' => 'http://careersandjobs.com.au/display-job/3649',
            'content_type' => 'text/html; charset=utf-8',
            'response_code' => 'OK',
            'data_type' => 'title_not_found'
        ),
        (int) 1 => array(
            'url' => 'http://bawbawshire.currentjobs.com.au/cvbuilder/apply+for+this+job/no/1225724',
            'sid' => '3726',
            'title' => 'Program &a',
            'company_name' => 'Baw Baw Shire Council',
            'our_link' => 'http://careersandjobs.com.au/display-job/3726',
            'content_type' => 'text/html; charset=utf-8',
            'response_code' => 'OK',
            'data_type' => 'title_not_found'
        ),
        (int) 2 => array(
            'url' => 'http://bawbawshire.currentjobs.com.au/cvbuilder/apply+for+this+job/no/1225826',
            'sid' => '3727',
            'title' => 'Road Netwo',
            'company_name' => 'Baw Baw Shire Council',
            'our_link' => 'http://careersandjobs.com.au/display-job/3727',
            'content_type' => 'text/html; charset=utf-8',
            'response_code' => 'OK',
            'data_type' => 'title_not_found'
        )
    )
)

这是我在outputs变量被控制器中的 set 函数设置之前从变量中得到的

4

1 回答 1

-1

您选择使用 CakePHP 的任何原因？因为您似乎没有使用它的功能！

您正在使用文字 SQL 查询，因此基本上跳过了 Models功能。

您是从Controller输出内容吗？使用输出缓冲时要小心，这可能与 CakePHP 的内部工作相冲突，后者在许多情况下也依赖于输出缓冲。因为您已经在此处输出内容 (ob_flush())，所以您将在到达您的视图之前输出您的内容..

通常我会指出手册中的具体点，但是，因为这里有很多错误，我建议从头开始阅读

于 2013-03-23T09:33:53.673 回答