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如果我有一个 4x1 单元结构，它代表a=[A1 A2 A3 A4]：

a=cell(4,1)
a{1}=[1 3 1 0]
a{2}=[3 3 3 3]
a{3}=[3 2 3 2]
a{4}=[3 3 3 2]

B=[1 1 1 2]; %priority

我想做以下事情：

选择与优先级相对应的单元格B=[1 1 1 2]（其中B=1最高优先级和A=3）
这意味着，找到任何以 [3 3 3 #] 开头的单元格，其中所有优先级都是 1 B。

理想的答案应该是： a{2}=[3 3 3 3]和a{4}=[3,3,3,2]

我的尝试是添加这个：

[P arrayind]=min(B) % problem is that arrayind return index=1 only .. not all indices
if P==1
   arrayindex = 1:4 ; %look at each index of the array
   c = a(cellfun(@(x) ismember(x(arrayindex), 3), a));
end

但是，这给了我一个错误说明：

Error using cellfun
Non-scalar in Uniform output, at index 1, output 1.
Set 'UniformOutput' to false.

通过调整代码以适应此错误：

c = a(cellfun(@(x) ismember(x(arrayindex), 3), a,'UniformOutput',false));

I get this error :

Error using subsindex
Function 'subsindex' is not defined for values of class 'cell'.

现在我被困在这一点上。

4

1 回答 1

1

这可能不是一个优雅的答案，但它是有效的：

%The input cell array.
a = cell(4,1);
a{1} = [1 3 1 0];
a{2} = [3 3 3 3];
a{3} = [3 2 3 2];
a{4} = [3 3 3 2];

%The input priority array.
B = [1 1 1 2];

%The output cell array: preallocated for efficiency.
c = cell(size(a));

j = 1;
for i = 1:size(a,1)
%For each i
    if(all(((cell2mat(a(i))==3)&(B==1))==(B==1)))
    %"cell2mat" converts the cell arrays into easily comparable number arrays.
    %"X==Y" for matrices of the same size, will give you a result matrix of the same size with 1 where the values are equal and 0 elsewhere.
    %Thus, "cell2mat(a(i))==3" would compare the number matrices represented by "a{i}" with "3".
    %"(cell2mat(a(i))==3)&(B==1)" would do a logical AND operation with "B==1", that is, "[1 1 1 0]".
    %In short, since you want whereever "a{i}" is 3 when "B" is 1, we want those "a{i}" where the comparison stated above is the same as "B==1".
    %If the result array is the same as "B=1", we get "[1 1 1 1]" as the result of the comparison "((cell2mat(a(i))==3)&(B==1))==(B==1)".
    %The function "all" checks whether the input to it is completely non-zero: here if we get a "[1 1 1 1]" "all" will give us 1, else 0.
        c{j} = a{i};
        %Insert result array into "c" when condition is satisfied.

        j = j + 1;
        %Increment the index of "c".
    end
end


c = c(1:j-1);
%Truncate unused rows of "c".

cell2mat(c)
%Displays the value of "c" as computed.
于 2013-03-22T18:50:09.643 回答