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我正在 android 中创建一个 HTTPUrlConnection 并准备它的帖子，如下所示

urlConnection = (HttpURLConnection) url.openConnection();

urlConnection.setRequestProperty("content-type", "application/json");
byte [] encoded = Base64.encode((username+":"+password).getBytes("UTF-8"), Base64.DEFAULT); 
//Basic Authorization               
urlConnection.setRequestProperty("Authorization", "Basic "+ new String(encoded, "UTF-8"));
urlConnection.setDoInput(true);
urlConnection.setDoOutput(true);

//This gets implicitly set when DoOutput is True, but still let it be               
urlConnection.setRequestMethod("POST");

//Required for POST not to return 404 when used on with a host:port combination
//http://stackoverflow.com/questions/5379247/filenotfoundexception-while-getting-the-inputstream-object-from-httpurlconnectio
urlConnection.setRequestProperty("User-Agent","Mozilla/5.0 (Macintosh; Intel Mac OS X 10.8; rv:17.0) Gecko/20100101 Firefox/17.0");
urlConnection.setRequestProperty("Accept","*/*");

然后我准备 JSON 并将其写入OutputStream连接的

JSONObject jsonObject = new JSONObject();
jsonObject.put("key1", "value1");
jsonObject.put("key2", "value2");



outputStreamWriter = urlConnection.getOutputStream ();
outputStreamWriter.write(jsonObject.toString().getBytes());


finally {
    if (outputStreamWriter != null) try { outputStreamWriter.close(); } catch (IOException logOrIgnore) {}
            }

当我发出请求时，我的状态为 500，因为我的服务器收到一个空的 POST 数据，它是无效的 json。

在 Web 浏览器和 curl 上也是如此。GET 在具有相同参数的 android 上工作。我错过了什么？应该为 POST 请求设置的方式参数的顺序有问题吗？

4

1 回答 1

1

我能够让它工作。下面的代码片段

创建要发送的数据，注意所需的转义引号

List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(3);

nameValuePairs.add(new BasicNameValuePair("\A\"", "\"/api/v1/a/1/\""));

nameValuePairs.add(new BasicNameValuePair("\"B\"", "\"/api/v1/b/1/\""));

nameValuePairs.add(new BasicNameValuePair("\"C\"", "\"Hello from Android\""));

创建客户端并设置标头

HttpClient httpclient = new DefaultHttpClient();

HttpPost httppost = new HttpPost(urlToPost);

httppost.setHeader("content-type", "application/json");

设置授权标头

String encoded = "Basic " + Base64.encodeToString((username+":"+password).getBytes("UTF-8"), Base64.URL_SAFE|Base64.NO_WRAP);

httppost.setHeader("Authorization",encoded);

将数据字符串化并将其设置为 POST 请求中的 HTTP 参数

StringEntity entity = new StringEntity(getQueryJSON(nameValuePairs));

httppost.setEntity(entity);

HttpResponse response = httpclient.execute(httppost);

if(response!=null){

InputStream in = response.getEntity().getContent(); //Get the data in the entity

readStream(in);

}

将 JSON 编码为字符串 private String getQueryJSON(List params) 的实用函数抛出 UnsupportedEncodingException

{

    StringBuilder result = new StringBuilder();

    boolean first = true;

    for (NameValuePair pair : params)

    {

    if (first){

        first = false;

        result.append("{");

    }else

        result.append(",");


    result.append(pair.getName());

    result.append(":");

    result.append(pair.getValue());


    }

    result.append("}");

    return result.toString();

}
于 2013-03-28T08:14:13.683 回答