sql - 如何在 SQL 中按任意条件排序

Question

我有下表：

CREATE TABLE Bable
    (
     id int identity primary key, 
     name varchar(20), 
     about varchar(30)
    );
INSERT INTO Bable (name,about) VALUES
('ООО Name Firm 1','texttexttexttext'),
('ООО Name Firm 2','texttexttexttext'),
('ООО Name Firm 3','texttexttexttext'),
('ООО Name Firm 4','texttexttexttext'),
('ООО Name Firm 5','texttexttexttext'),
('ООО Name Firm $1','texttexttexttext'),
('ООО Name Firm $2','texttexttexttext'),
('ООО Name Firm $3','texttexttexttext'),
('ООО Name Firm 6','texttexttexttext'),
('ООО Name Firm 7','texttexttexttext')

我可以编写如下查询：

SELECT * FROM Bable WHERE about = 'texttexttexttext'

如何更改此查询以返回排序的结果，使得名称包含“$”的那些首先出现，然后是那些没有的，然后每个组按name升序排序？

表结构在这里

Answer 1

SELECT *
FROM   Bable
ORDER  BY CASE WHEN name LIKE '%$..' THEN 0 ELSE 1 END,
          Name 

• SQLFiddle 演示

Answer 2

你可以这样做charatindex

SELECT * FROM Bable WHERE about = 'texttexttexttext'
Order by Case When CHARINDEX('$',name)>0 Then 0 Else 1 End,name

Answer 3

select * from Bable 
order by charindex('$',name,0) desc, name asc

SQL 小提琴演示