我正在尝试使用 linq to xml 生成一段 xml 数据。
XNamespace xsins = XNamespace.Get("http://www.w3.org/2001/XMLSchema-instance");
XAttribute xsiniltrue = new XAttribute(xsins+"Exists", "true");
XElement elem = new XElement("CustomerRecord", xsiniltrue);
这会在运行时为 xsins 生成前缀,它们看起来很假。
<Fragment>
<CustomerRecord p5:Exists="true" xmlns:p5="w3.org/2001/XMLSchema-instance"; />
</Fragment>
<Fragment>
<CustomerRecord p3:Exists="false" xmlns:p3="w3.org/2001/XMLSchema-instance"; />
</Fragment>
合并为
<Fragment xmlns:p5="w3.org/2001/XMLSchema-instance"; >
<CustomerRecord p5:Exists="true" />
<CustomerRecord p5:Exists="false" />
</Fragment>
还尝试使用 XMLWriter,
XNamespace xsins = XNamespace.Get("http://www.w3.org/2001/XMLSchema-instance");
using (var writer = XmlWriter.Create(fullPath, settings))
{
writer.WriteStartDocument(true);
writer.WriteStartElement(string.Empty, "Company", "urn:schemas-company");
//writer.WriteAttributeString(xsins.GetName("xsi"), "http://www.w3.org/2001/XMLSchema-instance");
writer.WriteStartElement(string.Empty, "Add", "urn:schemas-company");
foreach (var qx in resultXMLs)
{
qx.WriteTo(writer);
}
writer.WriteEndElement();
writer.WriteEndElement();
writer.WriteEndDocument();
}
我终于破解了它(至少我希望),下面的部分解决了我的问题
using (var writer = XmlWriter.Create(fullPath, settings))
{
writer.WriteStartDocument(true);
writer.WriteStartElement(string.Empty, "Company", "urn:schemas-company");
writer.WriteAttributeString("xmlns", "xsi", null, "http://www.w3.org/2001/XMLSchema-instance");
writer.WriteStartElement(string.Empty, "Add", "urn:schemas-company");
foreach (var qx in fragments)
{
qx.SetAttributeValue(XNamespace.Xmlns + "xsi", xsins.ToString());
qx.WriteTo(writer);
}
writer.WriteEndElement();
writer.WriteEndElement();
writer.WriteEndDocument();
}