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我一直在计算员工在工资率变化时的年度应税金额。

salary_assigned_date | salary
-------------------------------
    2011-12-06          5000
    2012-01-05          10000
    2012-02-10          15000
    2012-04-08          20000
    2012-08-01          28000

现在，我 2012 年的应税金额（以月份计）应该是这样的：

我假设没有。一个月的天数为 30。

month   |   taxable_amount
-----------------------------------------------
  01            833.33 + 8333.33   /* Since salary has been changed 
                                      at 6th of month, 
                                      for 5 days, 
                                      taxable amount = 5000/30*5 
                                      => 833.33 
                                      and for remaining 25 days
                                      = 10000/30*25=> 8333.33
                                      and same case for remaining months.*/
  02            3000 + 10500
  03            15000
  04            4666.67 + 15333.33
  05            20000
  06            20000
  07            20000
  08            933.33 + 27066.67
  09            28000
  10            28000
  11            28000
  12            28000

我试图编写一个存储过程来计算应税金额，但我无法做到这一点。

有人可以帮忙吗？

4

1 回答 1

1

您需要一个 sql 语句将表中的记录连接到表中具有下一个薪水值的记录...您还需要使用 CTE（或任何 ** MySQL 等效项* 存在）来生成所有月份没有工资变化。* [感谢@Neville 的评论]

请原谅 SQL 服务器语法，我不会为您查找 MySQL 等价物……意图应该很清楚。我知道 MySQL 有它自己的函数，相当于 SQL 服务器的日期函数getdate()、、、DateDiff()和。DateAdd()Day()

 With Dates(dt) As
 ( Select min(salary_assigned_date) 
   From yourTable 
   Union All
   Select DateAdd(month,1, dt)
   from dates
   where dt < getdate())  -- replace getdate() with parameter for max date to calculate

  -- If MySQL has no equivalent to CTE, you need to generate a temp table with 
  -- these dates in it and use that instead of the [Dates] construction

   Select t.dt, t.salary/30.0 * (day(t.dt)-1) +
        + n.salary/30.0 * (31 - day(t.dt))
   From Dates d 
      join yourTable t On t.salary_assigned_date = 
                    (Select Min(salary_assigned_date) 
                     From test where salary_assigned_date >= d.dt)
      join yourTable n On n.salary_assigned_date = 
                    (Select Min(salary_assigned_date) 
                      From test where salary_assigned_date > d.dt)

   Select t.salary/30.0 * (day(t.salary_assigned_date)-1) +
        + n.salary/30.0 * (31 - day(t.salary_assigned_date))
   From table t
       join table n On n.salary_assigned_date =
                    (Select Min(salary_assigned_date) From table
                     Where salary_assigned_date > t.salary_assigned_date)
于 2013-03-21T14:30:06.940 回答