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我一直在尝试研究python，我想尝试捕捉服务器超时错误（以防我的互联网连接中断或其他情况）并添加一个计时器，使进程停止X秒（在我下面的代码中是2 秒）然后尝试再次继续该过程。尽管我相信我的逻辑是正确的（如果我错了，请纠正我），但我收到一个错误消息

Exception in thread Thread-1:
Traceback (most recent call last):
  File "C:\Python33\lib\threading.py", line 639, in _bootstrap_inner
    self.run()
  File "C:\Python33\lib\threading.py", line 825, in run
    self.function(*self.args, **self.kwargs)
TypeError: 'NoneType' object is not callable

我不太明白为什么我的计时器似乎触发和错误。这是我的代码：

import urllib.request
from threading import Timer

req = urllib.request.Request('http://www.nowebsitecontainsthisaddress.com')

def ServerTimeOut(e):
    timer_rest = Timer(2.0, print('Time Out Error:'))
    timer_rest.start()
    print (e.reason)

    while timer_rest.is_alive():
        pass


while True:

    try:
        url = urllib.request.urlopen(req)
        break
    except urllib.error.HTTPError as e:
        ServerTimeOut(e)
        req = urllib.request.Request('http://www.google.com')
    except urllib.error.URLError as e:
        ServerTimeOut(e)
        req = urllib.request.Request('http://www.google.com')

使用的操作系统是windows7

更新：嗨，伙计们，我尝试将我的代码调整为这个，并且不再返回错误。我确实希望有人可以让我了解为什么会引发错误。谢谢^^，

import urllib.request
from threading import Timer

req = urllib.request.Request('http://www.nowebsitecontainsthisaddress.com')

def printMessage():
    print('Time Out Error:')

def ServerTimeOut(e):
    timer_rest = Timer(2.0, printMessage)
    timer_rest.start()

    print (e.reason)

    while timer_rest.is_alive():
        pass

while True:

    try:
        url = urllib.request.urlopen(req)
        break
    except urllib.error.HTTPError as e:
        ServerTimeOut(e)
        req = urllib.request.Request('http://www.google.com')
    except urllib.error.URLError as e:
        ServerTimeOut(e)
        req = urllib.request.Request('http://www.google.com')
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1 回答 1

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您在构造 Timer 时调用 print 函数。构建 Timer 的正确方法是Timer(2.0, print, 'Time Out Error').

于 2013-03-21T06:20:14.437 回答