1

我有一个看起来像这样的数组：

{"calendar":{"date":"1","event":"1","description":"","code":"lab"}}

我想在这个数组中输入一个新数组，但在日历中以实现这个输出：

{"calendar":
    {"date":"1","event":"1","description":"","code":"lab"}
    {"date":"2","event":"2","description":"","code":"lab"}
}

这一切都发生在表单帖子中。

<?php 
$dy_date = $_GET['dy_date'];
$dy_event = $_GET['dy_event'];
$dy_description = $_GET['dy_description'];
$dy_code = $_GET['dy_code'];

$calendar = array("calendar" => array("date" => $dy_date, "event" => $dy_event, "description" => $dy_description, "code"=> $dy_code));


$calendar_check = json_decode(file_get_contents('../calendar_dynamic.js'),true);

$updated_cal = array();
foreach($calendar_check as $data){
    $updated_cal["date"] = $dy_date;
    $updated_cal["event"] = $dy_event;
    $updated_cal["description"] = $dy_description;
    $updated_cal["code"] = $dy_code;
    $updated_cal = array_merge($calendar_check['calendar'], $updated_cal);
    $filename = "../calendar_dynamic.js";
    file_put_contents($filename, json_encode($updated_cal), FILE_APPEND);
}

?>

我似乎无法将添加的数组合并到现有数组中的正确位置。

想法？

4

2 回答 2

1

试试这个

$filename = "../uc3_stats/calendar_dynamic.js";

$dy_date = $_GET['dy_date'];
$dy_event = $_GET['dy_event'];
$dy_description = $_GET['dy_description'];
$dy_code = $_GET['dy_code'];

$newentry_calendar = array("calendar" => array("date" => $dy_date, "event" => $dy_event, "description" => $dy_description, "code"=> $dy_code));

$old_calendar = json_decode(file_get_contents($filename),true);

$new_calendar = $old_calendar; //keep old entries 
$new_calendar['calendar'][] = $newentry_calendar['calendar']; //add new entry
file_put_contents($filename, json_encode($new_calendar)); // save to file

如果你愿意，你可以缩短它，但这尽可能接近你的代码；）

于 2013-03-21T02:05:49.023 回答
1

我会使用 array_push 函数而不是 array_merge，因为在你的情况下，array_merge 改变了返回数组的结构，因为你将内部数组与新数组结合起来。

array_push ($calendar_check['calendar'], $updated_cal)
于 2013-03-21T02:09:11.690 回答