我正在为一个班级做家庭作业，并且正在寻找一些有用的指示，而不是完整的解决方案。基本上，我必须编写一个 Java 程序，它读取一个文本文件并逐行列出信息，列出行号，最后打印出最大值和最小值以及与每个相关的年份。文本文件包含一年和那一年的温度。因此，它列出了类似“1900 50.9”的内容。我不打算使用阵列或扫描仪，这是作业的一部分。我已经能够成功地让程序根据行数逐行打印出每年和相应的温度。有人告诉我，并且确实使用了 while 循环。现在，我唯一的问题是以某种方式访问文本文件，我可以以某种方式区分所有温度，哪个是最大值，哪个是最小值，每个发生在哪一年。我直到现在才寻求帮助，因为我想自己弄清楚，但是作业不再值得任何应得的功劳到迟到的处罚。任何帮助将不胜感激，因为我仍然想解决这个问题。谢谢。
这就是我所拥有的。
public class main {
/**
* @param args the command line arguments
*/
public static void main(String[] args) throws Exception {
File temps = new File ("temps.txt"); //Creates path to temps.txt file
FileReader textReader = new FileReader (temps); //Input information from temps.txt file into file reader
BufferedReader kb = new BufferedReader (textReader); //Use buffered reader to hold temps.txt file info from the file reader
String tempList; //Create string variable named tempList
int lineCount = 0; //Create integer variable named lineCount
String sep = ": Temp "; //Create string variable named sep (short for separation) and set it equal to the literal string ":"
String space = " "; //Create string variable named space and set it equal to an actual space between texts
System.out.println("The following is the provided information from the file input. ");
while ((tempList = kb.readLine()) !=null) { //while loop stating that as long as the text file still has values to read (is not null), continue to execute
System.out.println("Line " + lineCount++ + ": Year " + tempList.replace(space, sep)); //Prints out the line number (lineCount++), the info from the temps.txt file with a ":" between the year and the number (tempList.replace (space,sep)
}
}
}
到目前为止的输出是这样的：
Line 0: Year 1900: Temp 50.9
Line 1: Year 1901: Temp 49
Line 2: Year 1902: Temp 49.7
Line 3: Year 1903: Temp 49.5
Line 4: Year 1904: Temp 47.1
Line 5: Year 1905: Temp 49.1
等等一路...
Line 99: Year 1999: Temp 52.7
BUILD SUCCESSFUL (total time: 0 seconds)