我想知道如何确定 GPS 的状态,如果状态不同,AVAILABLE
我不会创建侦听器来节省电池。
但在执行中,始终输入else
create theLocationListener
而不是if
.
这是我的代码
public class UpdateGPS extends Thread{
public void run(){
while (true){
try{
getGPS();
sleep(30000); //Update GPS for each 30secs
}
catch(Exception e){}
}
}
}
public void getGPS() {
String state = "RUNNING";
BlackBerryCriteria myCriteria = new BlackBerryCriteria(GPSInfo.GPS_MODE_ASSIST);
try {
locationProvider = LocationProvider.getInstance(myCriteria);
if (locationProvider != null) {
if (locationProvider.getState() != locationProvider.AVAILABLE) {
state= "STOP";
}
else {
locationProvider.setLocationListener(
new LocationListenerImplementacion(),valor_reintento, -1, -1);
}
}
}
catch(Exception e) {}
}
private class LocationListenerImplementacion implements LocationListener {
public void locationUpdated(LocationProvider provider,Location location) {
if (location.isValid()) {
//GET DATA
}
else {}
public void providerStateChanged(LocationProvider provider, int newState){
}
}