15

使用 SQL Server 2008，我试图让其中一些列返回为 $xxx,xxx.xx

这是我正在使用的查询（这个查询然后一些更新只是为了计算数字并##tempshow在最后选择）

SELECT 
    CASE GROUPING(s.StoreID) WHEN 1 THEN '' ELSE s.StoreID END [StoreID],
    CASE GROUPING(p.VendorID) WHEN 1 THEN '' ELSE p.VendorID END [VendorID],
    SUM(d.Quantity) AS [UnitSold],
    CAST(SUM(d.amount * d.quantity) AS DECIMAL(18,2)) AS Amount, 
    CAST(SUM(d.Discount) AS DECIMAL(18,2)) AS Discount,
    CAST(SUM((d.Amount * d.Quantity - d.Discount)) AS DECIMAL(18,2)) AS ExtSold,
    CAST(SUM(d.Cost * d.Quantity) AS DECIMAL(18,2)) AS Cost,
    CAST(0 AS DECIMAL(18,2)) AS Profit,
    CAST(0 AS DECIMAL(18,2)) AS OnHand,
    CAST(0 AS DECIMAL(18,2)) AS OnHandRetail,
    CAST(0 AS DECIMAL(18,2)) AS OnHandCost,
    CAST(0 AS DECIMAL(18,2)) AS ReceivedCost,
    CAST(0 AS DECIMAL(18,2)) AS ReceivedRetail,
    CAST(0 AS DECIMAL(18,2)) AS ReceivedQty,
    CAST(0 AS DECIMAL(18,2)) AS Margin,
    CAST(0 AS DECIMAL(12,2)) AS TurnOver,
    CAST(0 AS INTEGER) AS OnOrder 
INTO
    ##tempshow
FROM 
    RPTrs s,
    RPTrsd d,
    RPIv i,
    RPProducts p
WHERE 
    s.ReceiptNO = d.ReceiptNO and 
    s.StoreID = d.StoreID and 
    i.UPC = d.UPC and 
    i.StoreID = d.StoreID and 
    p.ProductID = i.IVProduct and 
    s.StoreID = '01' and
    s.TRSDate > GETDATE()-20 and 
    p.Service = 0 
GROUP BY 
    GROUPING SETS((s.StoreID,p.VendorID),())

哪个返回： 在此处输入图像描述

我试过了

CAST(SUM(d.amount * d.quantity) AS MONEY) AS Amount,

和

SUM(CAST((d.amount * d.quantity) AS MONEY)) AS Amount,

预期输出（加上与此列相同的其他列Amount）：

  |StoreID | VendorID | UnitSold | Amount
---------------------------------------------
1 | 01     | 0000     | 0        | $0.00
2 | 01     | am       | 62       | $6,275.00
3 | 01     | AO       | 58       | $18,964.00
4 | 01     | payless  | 6        | $1,383.36
5 |        |          | 126      | $26,622.36

我需要Amount, Discount, ExtSold, Cost, Profit, OnHandRetail, OnHandCost, ReceivedCost, ReceivedRetail采用货币格式

4

2 回答 2

25

这是应该在表示层上完成的事情，但是如果您需要在 sql 中执行此操作，您可以使用：

'$'+convert(varchar(50), CAST(amount as money), -1) amount

这是一个例子：

;with cte (amount)
as
(
    select 123254578.00 union all
    select 99966.00 union all
    select 0.00 union all
    select 6275.00 union all 
    select 18964.00 union all 
    select 1383.36 union all
    select 26622.36
)
select '$'+convert(varchar(50), CAST(amount as money), -1) amount
from cte

请参阅SQL Fiddle with Demo。这将返回：

|          AMOUNT |
-------------------
| $123,254,578.00 |
|      $99,966.00 |
|           $0.00 |
|       $6,275.00 |
|      $18,964.00 |
|       $1,383.36 |
|      $26,622.36 |

注意：这在 SQL Server 2012 中会容易得多，因为您可以使用FORMAT()

;with cte (amount)
as
(
    select 123254578.00 union all
    select 99966.00 union all
    select 0.00 union all
    select 6275.00 union all 
    select 18964.00 union all 
    select 1383.36 union all
    select 26622.36
)
select '$'+FORMAT(amount,'#,0.0000') amount
from cte

请参阅带有演示的 SQL Fiddle

于 2013-03-20T17:47:05.720 回答
11

添加到 bluefeet 的答案，SQL 2012 中可用的 FORMAT 函数可以这样完成：

SELECT FORMAT(12345.6789, 'C', 'en-us')

C 表示货币，最后一个参数是文化。如果您希望您的应用程序是多语言的，那么文化很重要，因为它会处理美元（或欧元）符号和千位分隔符之类的东西。例如：

SELECT 
FORMAT(12345.6789, 'C', 'en-us') as "USA", 
FORMAT(12345.6789, 'C', 'fr-ca') as "French Canada", 
FORMAT(12345.6789, 'C', 'fr-fr') as "French France",
FORMAT(12345.6789, 'C', 'hi-in') as "Hindi India"

会给出这个结果：

USA            French Canada        French France     Hindi India
-----------    -------------        --------------    --------------
$12,345.68     12 345,68 $          12 345,68 €       ₹ 12,345.68
于 2016-07-22T16:32:37.423 回答