android - 更改复选框值而不触发 onCheckChanged

Question

我已经setOnCheckedChangeListener为我的checkbox

有没有办法我可以打电话

checkbox.setChecked(false);

在不触发onCheckedChanged

score 307 · Accepted Answer

不，你不能这样做。该onCheckedChanged方法直接从调用setChecked。您可以执行以下操作：

mCheck.setOnCheckedChangeListener (null);
mCheck.setChecked (false);
mCheck.setOnCheckedChangeListener (mListener);

查看CheckBox 的来源，以及实现setChecked：

public void  setChecked(boolean checked) {
    if (mChecked != checked) {
        mChecked = checked;
        refreshDrawableState();

        // Avoid infinite recursions if setChecked() is called from a listener
        if (mBroadcasting) {
            return;
        }

        mBroadcasting = true;
        if (mOnCheckedChangeListener != null) {
            mOnCheckedChangeListener.onCheckedChanged(this, mChecked);
        }

        if (mOnCheckedChangeWidgetListener != null) {
            mOnCheckedChangeWidgetListener.onCheckedChanged(this, mChecked);
        }

        mBroadcasting = false;            
    }
}

score 110 · Accepted Answer

在 OnCheckedChangeListener 中添加此代码：

if(!compoundButton.isPressed()) {
            return;
}

这将帮助我们确定天气复选框状态是否以编程方式或通过用户操作进行了更改。

score 29 · Accepted Answer

实现此目的的另一种可能方法是使用自定义 CheckBox ，它可以让您选择是否要调用侦听器：

public class CheckBox extends AppCompatCheckBox {
    private OnCheckedChangeListener mListener;

    public CheckBox(final Context context) {
        super(context);
    }

    public CheckBox(final Context context, final AttributeSet attrs) {
        super(context, attrs);
    }

    public CheckBox(final Context context, final AttributeSet attrs, final int defStyleAttr) {
        super(context, attrs, defStyleAttr);
    }

    @Override
    public void setOnCheckedChangeListener(final OnCheckedChangeListener listener) {
        mListener = listener;
        super.setOnCheckedChangeListener(listener);
    }

    public void setChecked(final boolean checked, final boolean alsoNotify) {
        if (!alsoNotify) {
            super.setOnCheckedChangeListener(null);
            super.setChecked(checked);
            super.setOnCheckedChangeListener(mListener);
            return;
        }
        super.setChecked(checked);
    }

    public void toggle(boolean alsoNotify) {
        if (!alsoNotify) {
            super.setOnCheckedChangeListener(null);
            super.toggle();
            super.setOnCheckedChangeListener(mListener);
            return;
        }
        super.toggle();
    }
}

Kotlin 版本，如果您愿意：

class CheckBox @JvmOverloads constructor(context: Context, attrs: AttributeSet? = null, defStyleAttr: Int = 0) : AppCompatCheckBox(context, attrs, defStyleAttr) {
    private var listener: CompoundButton.OnCheckedChangeListener? = null

    override fun setOnCheckedChangeListener(listener: CompoundButton.OnCheckedChangeListener?) {
        this.listener = listener
        super.setOnCheckedChangeListener(listener)
    }

    fun setChecked(checked: Boolean, alsoNotify: Boolean) {
        if (!alsoNotify) {
            super.setOnCheckedChangeListener(null)
            super.setChecked(checked)
            super.setOnCheckedChangeListener(listener)
            return
        }
        super.setChecked(checked)
    }

    fun toggle(alsoNotify: Boolean) {
        if (!alsoNotify) {
            super.setOnCheckedChangeListener(null)
            super.toggle()
            super.setOnCheckedChangeListener(listener)
            return
        }
        super.toggle()
    }
}

示例用法：

checkBox.setChecked(true,false);

score 11 · Accepted Answer

您只需使用 setonclickListener ，它就可以正常工作，这是非常简单的方法，谢谢 :)

score 10 · Accepted Answer

对于任何偶然发现这一点的人，一种更简单的方法是在复选框上使用一个标签，然后在其侦听器上检查该标签（代码在 Kotlin 中）：

checkBox.tag = false
checkBox.setOnCheckedChangeListener{ buttonView, isChecked -> 
    if(checkBox.tag != true) {
        // Do some stuff
    } else {
        checkBox.tag = false
    }

然后，当您想忽略值更改时，在将 isChecked 设置为 true 之前，只需将标签设置为 true：

checkBox.tag = true
checkBox.isChecked = true

如果您担心可理解性，您还可以使用需要密钥的替代 setTag 方法将标签映射到密钥。但是，如果它全部包含在一个类中，那么几个注释字符串就足以解释发生了什么。

score 7 · Accepted Answer

将 Kotlin 的扩展与 @Shade answer 一起使用：

fun CompoundButton.setCustomChecked(value: Boolean,listener: CompoundButton.OnCheckedChangeListener) {
     setOnCheckedChangeListener(null)
     isChecked = value
     setOnCheckedChangeListener(listener)
}

score 7 · Accepted Answer

很简单，你在isPressed里面查一下setOnCheckedChangeListener

科特林

switch.setOnCheckedChangeListener { buttonView, isChecked ->
    when {        
        buttonView.isPressed -> {
            foo(isChecked)
        }
    }

score 4 · Accepted Answer

您可以将此 SafeCheckBox 类用作您的复选框：

public class SafeCheckBox extends AppCompatCheckBox implements CompoundButton.OnCheckedChangeListener {

    private OnSafeCheckedListener onSafeCheckedListener;

    private int mIgnoreListener = CALL_LISTENER;

    public static final int IGNORE = 0;
    public static final int CALL_LISTENER = 1;

    @Retention(RetentionPolicy.SOURCE)
    @IntDef({IGNORE, CALL_LISTENER})
    public @interface ListenerMode {
    }

    public SafeCheckBox(Context context) {
        super(context);
        init(context);
    }

    public SafeCheckBox(Context context, AttributeSet attrs) {
        super(context, attrs);
        init(context);
    }

    public SafeCheckBox(Context context, AttributeSet attrs, int defStyleAttr) {
        super(context, attrs, defStyleAttr);
        init(context);
    }

    /**
     * @param checkState     change state of the checkbox to 
     * @param mIgnoreListener true to ignore the listener else listener will be  notified
     */
    public void setSafeCheck(boolean checkState, @ListenerMode int mIgnoreListener) {
        if (isChecked() == checkState) return; //already in the same state no need to fire listener. 

        if (onSafeCheckedListener != null) { // this to avoid a bug if the user listens for the event after using this method and in that case he will miss first check
            this.mIgnoreListener = mIgnoreListener;
        } else {
            this.mIgnoreListener = CALL_LISTENER;
        }
        setChecked(checkState);
    }

    private void init(Context context) {
        setOnCheckedChangeListener(this);
    }


    public OnSafeCheckedListener getOnSafeCheckedListener() {
        return onSafeCheckedListener;
    }

    public void setOnSafeCheckedListener(OnSafeCheckedListener onSafeCheckedListener) {
        this.onSafeCheckedListener = onSafeCheckedListener;
    }

    @Override
    public void onCheckedChanged(CompoundButton buttonView, boolean isChecked) {

        if (onSafeCheckedListener != null)
            onSafeCheckedListener.onAlwaysCalledListener(buttonView, isChecked);// this has to be called before onCheckedChange
        if (onSafeCheckedListener != null && (mIgnoreListener == CALL_LISTENER)) {
            onSafeCheckedListener.onCheckedChanged(buttonView, isChecked);
        }
        mIgnoreListener = CALL_LISTENER;
    }

    /**
     * Listener that will be called when you want it to be called.
     * On checked change listeners are called even when the setElementChecked is called from code. :(
     */
    public interface OnSafeCheckedListener extends OnCheckedChangeListener {
        void onAlwaysCalledListener(CompoundButton buttonView, boolean isChecked);
    }
}

然后你可以打电话： -

setSafeCheck(true,ListenerMode.IGNORE);// OnCheckedChange listener will not be notified

score 3 · Accepted Answer

在检查单选按钮之前将 null 设置为 changeListener。您可以在选中单选按钮后再次设置监听器。

radioGroup.setOnCheckedChangeListener(null);
radioGroup.check(R.id.radioButton);
radioGroup.setOnCheckedChangeListener(new 

RadioGroup.OnCheckedChangeListener() {
   @Override
   public void onCheckedChanged(RadioGroup radioGroup, @IdRes int i) {

   }
});

score 3 · Accepted Answer

我认为最简单的解释
可能会有所帮助）

public class ProgrammableSwitchCompat extends SwitchCompat {

    public boolean isCheckedProgrammatically = false;

    public ProgrammableSwitchCompat(final Context context) {
        super(context);
    }

    public ProgrammableSwitchCompat(final Context context, final AttributeSet attrs) {
        super(context, attrs);
    }

    public ProgrammableSwitchCompat(final Context context, final AttributeSet attrs, final int defStyleAttr) {
        super(context, attrs, defStyleAttr);
    }

    @Override
    public void setChecked(boolean checked) {
        isCheckedProgrammatically = false;
        super.setChecked(checked);
    }

    public void setCheckedProgrammatically(boolean checked) {
        isCheckedProgrammatically = true;
        super.setChecked(checked);
    }
}

用它

@Override
public void onCheckedChanged(CompoundButton compoundButton, boolean on) {
    if (((ProgrammableSwitchCompat) compoundButton).isCheckedProgrammatically) {
        return;
    }
    //...
    ((ProgrammableSwitchCompat) compoundButton).setCheckedProgrammatically(true);
    //...
    ((ProgrammableSwitchCompat) compoundButton).setCheckedProgrammatically(false);
    //...
}

使用将触发setChecked(boolean)功能
就是所有

科特林

class MyCheckBox @JvmOverloads constructor(
    context: Context,
    attrs: AttributeSet? = null,
    defStyleAttr: Int = R.attr.switchStyle
) : AppCompatCheckBox(context, attrs, defStyleAttr) {

    var programmatically = false

    override fun setChecked(checked: Boolean) {
        programmatically = false
        super.setChecked(checked)
    }

    fun setCheckedProgrammatically(checked: Boolean) {
        programmatically = true
        super.setChecked(checked)
    }
}

score 3 · Accepted Answer

这是我使用的一个简单解决方案：
定义自定义侦听器：

class CompoundButtonListener implements CompoundButton.OnCheckedChangeListener {

    boolean enabled = false;

    @Override
    public void onCheckedChanged(CompoundButton compoundButton, boolean checked) {

    }

    void enable() {
        enabled = true;
    }

    void disable() {
        enabled = false;
    }

    boolean isEnabled() {
        return enabled;
    }
}

初始化：

CompoundButtonListener checkBoxListener = new CompoundButtonListener() {
    @Override
    public void onCheckedChanged(CompoundButton compoundButton, boolean checked) {
        if (isEnabled()) {
            // Your code goes here
        }
    }
};
myCheckBox.setOnCheckedChangeListener(checkBoxListener);

用法：

checkBoxListener.disable();

// Some logic based on which you will modify CheckBox state
// Example: myCheckBox.setChecked(true)

checkBoxListener.enable();

score 2 · Accepted Answer

这个怎么样。尝试在视图中使用标签

mCheck.setTag("ignore");
mCheck.setChecked(true);
mCheck.setTag(null);

和

switch.setOnCheckedChangeListener(new CompoundButton.OnCheckedChangeListener() {
        @Override
        public void onCheckedChanged(CompoundButton compoundButton, boolean selected) {

            //If switch has a tag, ignore below
            if(compoundButton.getTag() != null)
                return; 

            if (selected) {
                // do something
            } else {
                // do something else
            }

        }
    });

score 2 · Accepted Answer

试试这个应该适合你！您也可以将其与 firebase 一起使用！

获取firebase数据！用这个！

databaseReference.child(user.getPhoneNumber()).child("Reqs").addValueEventListener(new ValueEventListener() {

        @Override
        public void onDataChange(DataSnapshot dataSnapshot) {
            SharedPreferences prefs = mContext.getSharedPreferences("uinfo", MODE_PRIVATE);
            String pno = prefs.getString("username", "No name defined");

            if(dataSnapshot.child(pno).getValue(String.class).equals("acc")){
                holder.acc.setChecked(true);
            }else{
                holder.acc.setChecked(false);
            }
        }

        @Override
        public void onCancelled(DatabaseError databaseError) {
            // Getting Post failed, log a message
            Log.w("dfs", "loadPost:onCancelled", databaseError.toException());
            // ...
        }
    });

之后当用户做某事！

holder.acc.setOnCheckedChangeListener(new CompoundButton.OnCheckedChangeListener() {
            @Override
            public void onCheckedChanged(CompoundButton buttonView, boolean isChecked) {
                if(isChecked) {
                    if(buttonView.isPressed()) {
                        //your code
                    }
                }
                else {
                    if(buttonView.isPressed()) {
                       //your code
                    }
                }
            }
        });

score 1 · Accepted Answer

我发现上面所有的答案都太复杂了。为什么不使用简单的布尔值创建自己的标志？

只需使用带有布尔值的简单标志系统。创建boolean noListener. 每当您想在不运行任何代码的情况下打开/关闭开关（在此示例中，表示为runListenerCode()，只需noListener=true在调用之前设置switch.setChecked(false/true)

switch.setOnCheckedChangeListener(new CompoundButton.OnCheckedChangeListener() {
           @Override
           public void onCheckedChanged(CompoundButton compoundButton, boolean selected) {
               if (!noListener) { //If we want to run our code like usual
                   runListenerCode();
               } else { //If we simply want the switch to turn off
                   noListener = false;
               }
           });

使用简单标志的非常简单的解决方案。最后，我们noListener=false再次设置，以便我们的代码继续工作。希望这可以帮助！

score 1 · Accepted Answer

我使用了ReentrantLock, 并在设置时将其锁定isChecked：

科特林：

// lock when isChecked is being set programmatically
val isBeingProgrammaticallySet = ReentrantLock()

// set isChecked programmatically
isBeingProgrammaticallySet.withLock()
{
    checkbox.isChecked = true
}

// do something only when preference is modified by user
checkbox.setOnCheckedChangeListener()
{
    _,isChecked ->
    if (isBeingProgrammaticallySet.isHeldByCurrentThread.not())
    {
        // do it
    }
}

score 1 · Accepted Answer

isPressed()检查过一次onCreate()。checkbox.isPressed()每次您onCheckChangeListener的复选框更改时添加检查。

score 0 · Accepted Answer

我想使用反射是唯一的方法。像这样的东西：

CheckBox cb = (CheckBox) findViewById(R.id.checkBox1);
try {
    Field field = CompoundButton.class.getDeclaredField("mChecked");
    field.setAccessible(true);
    field.set(cb, cb.isChecked());
    cb.refreshDrawableState();
    cb.invalidate();
} catch (Exception e) {
    e.printStackTrace();
}

score 0 · Accepted Answer

我基于@Chris 回答用java 编写的解决方案：

chkParent.setOnCheckedChangeListener(new CompoundButton.OnCheckedChangeListener() {
            @Override
            public void onCheckedChanged(CompoundButton buttonView, boolean isChecked) {
                if(buttonView.getTag() != null){
                    buttonView.setTag(null);
                    return;
                }
                if(isChecked){
                    chkChild.setTag(true);
                    chkChild.setChecked(false);
                }
                else{
                    chkParent.setChecked(true);
                }
            }
});

chkChild.setOnCheckedChangeListener(new CompoundButton.OnCheckedChangeListener() {
            @Override
            public void onCheckedChanged(CompoundButton buttonView, boolean isChecked) {
                if(buttonView.getTag() != null){
                    buttonView.setTag(null);
                    return;
                }
                if(isChecked){
                    chkParent.setTag(true);
                    chkParent.setChecked(false);
                }
                else{
                    chkChild.setChecked(true);
                }
            }
});

2 个复选框，并且始终会选中一个（但最初必须选中一个）。将标记设置为 true 会阻止 onCheckedChanged 侦听器。

score 0 · Accepted Answer

public void setCheckedChangeListenerSwitch() {

    switch.setOnCheckedChangeListener(new CompoundButton.OnCheckedChangeListener() {
        @Override
        public void onCheckedChanged(CompoundButton compoundButton, boolean selected) {

            if (selected) {
                // do something
            } else {
                // do something else
            }

        }
    });

}

// Update state & reset listener (so onCheckedNot called)
public void updateSwitchState(boolean state){

    switch.setOnCheckedChangeListener(null);
    switch.setChecked(state);
    setCheckedChangeListenerSwitch();

}

score 0 · Accepted Answer

我真的不想在每次设置检查更改时都必须传递侦听器，也不想enabled用作确定是否应该设置值的一种方式（如果在设置值时我们已经禁用了开关会发生什么情况?)

相反，我正在使用带有 id 的标签和一些您可以调用的扩展方法：

fun CompoundButton.setOnCheckedWithoutCallingChangeListener(
    listener: (view: CompoundButton, checked: Boolean) -> Unit
) {
    setOnCheckedChangeListener { view, checked ->
        if (view.getTag(R.id.compound_button_checked_changed_listener_disabled) != true) {
            listener(view, checked)
        }
    }
    this.setTag(R.id.compound_button_enabled_checked_change_supported, true)
}

fun CompoundButton.setCheckedWithoutCallingListener(checked: Boolean) {
    check(this.getTag(R.id.compound_button_enabled_checked_change_supported) == true) {
        "Must set listener using `setOnCheckedWithoutCallingChangeListener` to call this method" 
    }

    setTag(R.id.compound_button_checked_changed_listener_disabled, true)
    isChecked = checked
    setTag(R.id.compound_button_checked_changed_listener_disabled, false)
}

现在您可以调用setCheckedWithoutCallingListener(bool)，它将强制执行正确的侦听器使用。

setChecked(bool)如果您仍然需要它，您仍然可以调用来触发侦听器

score 0 · Accepted Answer

这是一个非常易于使用的标记技术版本。

用法：

// Pass true to enable bypassing of the listener
button.setOnCheckedChangedListener(true) { _, isChecked ->
    // your usual code
}

// Use extension function to set the value and bypass the listener
button.setCheckedSilently(true)

它是通过几个实用程序扩展功能完成的：

inline fun CompoundButton.setOnCheckedChangeListener(canBypass: Boolean, crossinline listener: (CompoundButton, Boolean) -> Unit) {
    if (canBypass) {
        setOnCheckedChangeListener { view, isChecked ->
            if (view.tag != ListenerBypass) {
                listener(view, isChecked)
            }
        }
    } else {
        setOnCheckedChangeListener { view, isChecked -> listener(view, isChecked) }
    }
}

fun CompoundButton.setCheckedSilently(isChecked: Boolean) {
    val previousTag = tag
    tag = ListenerBypass
    this.isChecked = isChecked
    tag = previousTag
}

object ListenerBypass

android - 更改复选框值而不触发 onCheckChanged

21 回答 21

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