0

我可以这样做:

// View
<div>
<?php echo $this->myHelper($this); ?>
</div>

// View helper
public function __invoke($view)
{
   ...
   return $view->partial('page_nav', $someData);
}

我可以在视图助手中获取视图对象而不将其作为参数传递给视图吗?像这样:

// View
<div>
<?php echo $this->myHelper(); ?>
</div>

// View Helper factory
public function createService(ServiceLocatorInterface $pluginManager)
{        
    ...     
    $view = foo(); // maybe here I can get view?
    return new myHelper($view);
}

// View helper
public function __invoke()
{
   ...
   $view = $this->view;
   return $view->partial('page_nav', $someData);
}
4

1 回答 1

2
use Zend\View\Helper\AbstractHelper;

class MyHelper extends AbstractHelper {
    public function __invoke() {
        $view = $this->getView();
        // Do something with $view
    }
}
于 2013-03-20T11:23:08.953 回答