timestamp
如果将 an 添加interval
到 a 中,您将得到a timestamp
(请参阅日期/间隔算术)。
正如Benoit 注意到的那样,当它们超过大约 2.1e9 时,您不能指定以秒为单位的间隔:
SQL> SELECT numtodsinterval(2.2e9, 'SECOND'),
2 numtodsinterval(2.3e9, 'SECOND')
3 FROM dual;
NUMTODSINTERVAL(2.2E9,'SECOND' NUMTODSINTERVAL(2.3E9,'SECOND'
------------------------------- -------------------------------
+000024855 03:14:07.147483647 +000024855 03:14:07.147483647
这就是为什么您应该使用不会丢失精度的分钟数。例如,假设:TS
是unix时间戳(即一个数字):
SQL> variable ts number;
SQL> -- determining unix timestamp with nanosecond precision
SQL> BEGIN
2 :ts := (to_date('2099-01-01 01:02:03', 'yyyy-mm-dd hh24:mi:ss')
3 - date '1970-01-01') * 1000*60*60*24
4 + 123.456789;
5 END;
6 /
ts
---------
4070912523123,456789
SQL> select timestamp '1970-01-01 00:00:00'
2 + numtodsinterval((:ts)/1000/60, 'MINUTE')
3 from dual;
TIMESTAMP'1970-01-0100:00:00'+NUMTODSINTERVAL((:TS)/1000/60,'MINUTE')
---------------------------------------------------------------------------
2099-01-01 01:02:03.123456789