我使用 FineUploder 将图像上传到 Web 服务器。
javascript
function createUploader() {
var thumbnailuploader = new qq.FineUploader({
element: $('#thumbnail-fine-uploader')[0],
request: {
endpoint: '<%= ResolveUrl("~/Common/uploadhandler.ashx") %>'
},
multiple: false,
...
callbacks: {
onComplete: function (id, fileName, responseJSON) {
if (responseJSON.success) {
$('#imgPreview').html('<img src="../Uploaded/' + filename + '" alt="' + filename + '">');
}
}
}
});
}
window.onload = createUploader;
javascript 调用服务器uploadhandler.ashx
端,并成功上传文件。
public void ProcessRequest(HttpContext context)
{
.....
context.Response.ContentType = "application/json";
context.Response.Write("{\"success\":true}");
}
这里我需要用 json 响应返回另一个参数。如何向context.Response.Write("{\"success\":true}");
javascript 'onComplete' 方法添加另一个参数并从中读取它