在 JS 文件中,我正在执行此功能:
$(function() {
$(".button").click(function() {
//get the button's ID (which is equal to its row's report_id)
var emergency = this.id;
var button = this.attributes['name'].value;
var dataString = 'reportid=' + emergency;
alert(dataString);
if (button == "clockin") {
$.ajax({
type: "POST",
url: "/employeetimeclock.php",
data: dataString,
success: function() {
window.location = "/employeetimeclock.php";
}
});
} else if (button == "closereport") {
var r = confirm("Are you sure you want to close this report?\nThis action CANNOT be undone!");
if (r == true) {
$.ajax({
type: "POST",
url: "/closeemergencyreport.php",
data: dataString,
success: function() {
alert("Report Successfully Closed!");
window.location = "/closeemergencyreport.php";
},
error: function() {
alert("An error has occured, the report was not closed");
}
});
} else {
alert("Report was not closed.");
}
}
});
});
对于 else if(到 closeemergencyreport.php),该 php 脚本中的代码如下:
<?php
require_once("models/config.php");
require_once("models/header.php");
require_once("models/dbconnect.php");
$reportid = $_POST['reportid'];
var_dump($_POST);
$sql = "UPDATE emergency_report SET report_closed = '1' WHERE report_id IN ( $reportid )";
//execute and test if succesful
$result = mysql_query($sql) or die(mysql_error());
if($result){
} else{
}
?>
我在其他 3 个页面上做了同样的事情,它完美地工作,但这给我带来了麻烦,在那个 php 脚本上 VAR_DUMP 说它返回一个空数组。我已经阅读和重新阅读代码大约一个半小时了,所以我认为我已经筋疲力尽了,需要有一个外部的看法。我已经遍及整个网站,没有人找到适合我的解决方案。
我知道它正在发布,因为火虫在运行 javascript 的表单页面上显示了这个:http:
//i.imgur.com/hItdVU1.png(抱歉不能发布图片)