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我有一个文件上传脚本：

$allowedExts = array("gif", "jpeg", "jpg", "png");
$extension = end(explode(".", $_FILES["picture"]["name"]));
if ((($_FILES["picture"]["type"] == "image/gif") || ($_FILES["picture"]["type"] == "image/jpeg") || ($_FILES["picture"]["type"] == "image/jpg") || ($_FILES["picture"]["type"] == "image/png")) && in_array($extension, $allowedExts)):
    if($_FILES["picture"]["error"] > 0):
        echo "Error: " . $_Files["picture"]["error"];
    else:
        move_uploaded_file($_FILES["picture"]["tmp_name"], "/TnA/ProfilePics/" . $_SESSION['ID'] . "." . $extension);
    endif;
endif;

但我收到了错误：

Warning: move_uploaded_file(TnA/ProfilePics/1.jpg) [function.move-uploaded-file]: failed to open stream: No such file or directory in /home/content/91/9848191/html/TnA/webservice.php on line 1067

Warning: move_uploaded_file() [function.move-uploaded-file]: Unable to move '/tmp/php5nOdhI' to 'TnA/ProfilePics/1.jpg' in /home/content/91/9848191/html/TnA/webservice.php on line 1067

这是我的文件结构：

Web Host Root (I have another site here)
    -TnA (Root of this site)
        -index.html
        -webservice.php
        -ProfilePics
            -(My target location)

我应该使用什么相对目录 url？我已经尝试过ProfilePics/1.jpg，/ProfilePics/1.jpg两者都导致相同的错误。

编辑：

使用：

move_uploaded_file($_FILES["picture"]["tmp_name"], dirname(__FILE__) . "ProfilePics/" . $_SESSION['ID'] . "." . $extension);

我得到：

Warning: move_uploaded_file(/home/content/91/9848191/html/TnA/ProfilePics/1.jpg) [function.move-uploaded-file]: failed to open stream: No such file or directory in /home/content/91/9848191/html/TnA/webservice.php on line 1067
4

1 回答 1

3

您很可能在使用相关路径时遇到问题。如果您的上传脚本是 webservice.php，那么您实际上是在尝试将文件放入 /%webHostRoot%/ TnA / TnA /ProfilePics/ 目录。move_uploaded_file()在' 目标中使用完整路径。尝试使用类似的东西：

move_uploaded_file($_FILES["picture"]["tmp_name"], dirname(__FILE__)."ProfilePics/" . $_SESSION['ID'] . "." . $extension);

UPD：这是递归创建目录的函数：

function MkDirTree($path,$permissions = 0755, $compat_mode=true) {
    if (!$compat_mode) {
        $dirs = split("/",$path);
        $path = "";
        foreach ($dirs as $key=>$dir) {
            $path .= $dir."/";
            if ($dir!="" && !is_dir($path)) exec("mkdir -m ".$permissions." ".$path);
        }
    } else {
        $dirs = split("/",$path);
        $path = "";
        foreach ($dirs as $key=>$dir) {
            $path .= $dir."/";
            if ($dir!="" && !file_exists($path)) mkdir($path, $permissions);
        }
    }
    return file_exists($path);
}
于 2013-03-19T19:40:52.763 回答