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每当我在游戏中播放声音时，线程都会冻结，然后在声音播放完毕后继续。声音引擎的代码：

package com.kgt.platformer;

import java.io.File;
import java.io.IOException;    
import javax.sound.sampled.AudioFormat;
import javax.sound.sampled.AudioInputStream;
import javax.sound.sampled.AudioSystem;
import javax.sound.sampled.DataLine;
import javax.sound.sampled.LineUnavailableException;
import javax.sound.sampled.SourceDataLine;

public class Sound {
    private final static int BUFFER_SIZE = 12800000;
    private static File soundFile;
    private static AudioInputStream audioStream;
    private static AudioFormat audioFormat;
    private static  SourceDataLine sourceLine;

    /**
     * 
     * @param filename the name of the file that is going to be played
     *
     */
    public static void playSound(String filename){

        String strFilename = filename;

        try {
            soundFile = new File(strFilename);
        } catch (Exception e) {
            e.printStackTrace();
            System.exit(1);
        }

        try {
            audioStream = AudioSystem.getAudioInputStream(soundFile);
        } catch (Exception e){
            e.printStackTrace();
           System.exit(1);
        }

        audioFormat = audioStream.getFormat();

        DataLine.Info info = new DataLine.Info(SourceDataLine.class, audioFormat);
        try {
            sourceLine = (SourceDataLine) AudioSystem.getLine(info);
            sourceLine.open(audioFormat);
        } catch (LineUnavailableException e) {
            e.printStackTrace();
            System.exit(1);
        } catch (Exception e) {
            e.printStackTrace();
            System.exit(1);
        }


        sourceLine.start();

        int nBytesRead = 0;
        byte[] abData = new byte[BUFFER_SIZE];
        while (nBytesRead != -1) {
            try {
                nBytesRead = audioStream.read(abData, 0, abData.length);
            } catch (IOException e) {
                e.printStackTrace();
            }
            if (nBytesRead >= 0) {
                @SuppressWarnings("unused")
                int nBytesWritten = sourceLine.write(abData, 0, nBytesRead);
            }
        }

        sourceLine.drain();
        sourceLine.close();
    }
}

最终发生的是我开始游戏，它播放声音，游戏冻结然后继续。

4

2 回答 2

5

您可以启动一个线程来处理流的读取和写入。看看这里： 如何在 Java 中播放声音？

示例代码：

new Thread(new Runnable() {
  public void run() {
    Sound.playSound("Test.wav");
  }
}).start();
于 2013-03-19T18:31:16.520 回答
1

基于 Java 声音的Clip使用它自己的 (daemon) Thread。请参阅此示例，该示例将循环播放 2 个剪辑（尽管被警告，请调低音量）。另请注意，第二个剪辑需要一些时间才能加载。等到你看到JOptionPane- 然后两个剪辑都应该循环播放。

import java.net.URL;
import javax.swing.*;
import javax.sound.sampled.*;

public class LoopSounds {

    public static void main(String[] args) throws Exception {
        URL url1 = new URL(
            "http://pscode.org/media/leftright.wav");
        URL url2 = new URL("http://pscode.org/media/100_2817-linear.wav");
        Clip clip1 = AudioSystem.getClip();
        Clip clip2 = AudioSystem.getClip();
        // getAudioInputStream() also accepts a File or InputStream
        AudioInputStream ais1 = AudioSystem.
            getAudioInputStream( url1 );
        clip1.open(ais1);
        clip1.loop(Clip.LOOP_CONTINUOUSLY);

        AudioInputStream ais2 = AudioSystem.
            getAudioInputStream( url2 );
        clip2.open(ais2);
        clip2.loop(Clip.LOOP_CONTINUOUSLY);
        SwingUtilities.invokeLater(new Runnable() {
            public void run() {
                // A GUI element to prevent the Clip's daemon Thread
                // from terminating at the end of the main()
                JOptionPane.showMessageDialog(null, "Close to exit!");
            }
        });
    }
}
于 2013-03-20T02:55:27.837 回答