1

我需要创建一组 web 服务，这将由来自其他域的 javascript 请求。

我发现有一个很酷的跨域支持包：CORSFilter。

我看到，CORS 的实现是通过添加到 web.xml：

<web-app>
<filter>
    <filter-name>CORSFilter</filter-name>
    <filter-class>CORSFilter</filter-class>
</filter>
<filter-mapping>
    <filter-name>CORSFilter</filter-name>
    <url-pattern>/api/*</url-pattern>
</filter-mapping>

但我有自己的配置：

<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">

    <!-- The definition of the Root Spring Container shared by all Servlets and Filters -->
    <context-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>/WEB-INF/spring/root-context.xml</param-value>
    </context-param>

    <!-- Creates the Spring Container shared by all Servlets and Filters -->
    <listener>
        <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
    </listener>

    <!-- Processes application requests -->
    <servlet>
        <servlet-name>appServlet</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <init-param>
            <param-name>contextConfigLocation</param-name>
            <param-value>/WEB-INF/spring/appServlet/servlet-context.xml</param-value>
        </init-param>
        <load-on-startup>1</load-on-startup>
    </servlet>

    <servlet-mapping>
        <servlet-name>appServlet</servlet-name>
        <url-pattern>/*</url-pattern>
    </servlet-mapping>



</web-app>

当我尝试将 CORS 配置添加到我的 web.xml 时：

<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">

<!-- The definition of the Root Spring Container shared by all Servlets and Filters -->
<context-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>/WEB-INF/spring/root-context.xml</param-value>
</context-param>

<!-- Creates the Spring Container shared by all Servlets and Filters -->
<listener>
    <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>

<!-- Processes application requests -->
<servlet>
    <servlet-name>appServlet</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <init-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>/WEB-INF/spring/appServlet/servlet-context.xml</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
</servlet>

<servlet-mapping>
    <servlet-name>appServlet</servlet-name>
    <url-pattern>/*</url-pattern>
</servlet-mapping>

<filter>
    <filter-name>corsFilter</filter-name>
    <filter-class>com.thetransactioncompany.cors.CORSFilter</filter-class>
</filter>

<filter-mapping>
    <filter-name>corsFilter</filter-name>
    <servlet-name>/*</servlet-name>
</filter-mapping>

我收到一个错误：

    mar 19, 2013 2:17:08 PM org.apache.catalina.core.StandardContext startInternal
SEVERE: Error filterStart
mar 19, 2013 2:17:08 PM org.apache.catalina.core.StandardContext startInternal
SEVERE: Context [] startup failed due to previous errors

我应该如何实施它？

谢谢

4

2 回答 2

1

在“filter-mapping”部分，你有一个“servlet-name”标签，但里面实际上是一个 url 模式，而不是一个 servlet 名称。所以你应该有

<servlet-name>appServlet</servlet-name>

或者

<url-pattern>/*</url-pattern>
于 2013-04-04T09:28:35.970 回答
1

您可能应该考虑使用从Spring Framework 4.2 GA开始提供的本机 CORS 支持。有关更多详细信息，请参阅此博客文章。

如果您更喜欢继续使用Filter基于方法的方法，例如，如果您不使用 Spring MVC 而只是使用 Spring Web，那么CorsFilter还提供了 Spring。

于 2015-07-21T12:58:16.343 回答