python - PySide 程序崩溃处理程序

Question

我的程序在遇到错误时会发送电子邮件。有没有办法处理这个程序的崩溃并用这个程序发送关于它的电子邮件？

Answer 1

您正在寻找sys.excepthook，这里是一个例子：

#!/usr/bin/env python
#-*- coding:utf-8 -*-

import cStringIO, traceback

from PyQt4 import QtGui, QtCore

errorNotice = """
An unhandled exception occurred. Details will be reported
via an automatic email.
"""

class MyMessageBox(QtGui.QMessageBox):
    def __init__(self, *args, **kwargs):            
        super(MyMessageBox, self).__init__(*args, **kwargs)
        self.tracebackInfoStream = cStringIO.StringIO()

        self.setIcon(QtGui.QMessageBox.Critical)
        self.finished.connect(self.on_finished)

    def getTraceback(self, exceptionTraceback):
        traceback.print_tb(
            exceptionTraceback,
            None,
            self.tracebackInfoStream
        )

        self.tracebackInfoStream.seek(0)

        return self.tracebackInfoStream.read()

    def exceptHook(self, exceptionType, exceptionValue, exceptionTraceback):   
        tracebackInfo = self.getTraceback(exceptionTraceback)

        self.setDetailedText(tracebackInfo)
        self.setText(errorNotice)
        self.exec_()

    @QtCore.pyqtSlot()
    def on_finished(self):  
        QtGui.QApplication.quit()

class MyWindow(QtGui.QWidget):
    def __init__(self, parent=None):
        super(MyWindow, self).__init__(parent)

        self.pushButtonError = QtGui.QPushButton(self)
        self.pushButtonError.setText("Raise an Error!")
        self.pushButtonError.clicked.connect(self.on_pushButtonError_clicked)

        self.layoutVertical = QtGui.QVBoxLayout(self)
        self.layoutVertical.addWidget(self.pushButtonError)

    @QtCore.pyqtSlot()
    def on_pushButtonError_clicked(self):
        raise UserWarning("This is an error")

if __name__ == "__main__":
    import sys

    app = QtGui.QApplication(sys.argv)
    app.setApplicationName('MyWindow')

    myMessageBox = MyMessageBox()

    sys.excepthook = myMessageBox.exceptHook

    main = MyWindow()
    main.show()

    sys.exit(app.exec_())