3

再会

这个 SQL 脚本让我度过了一个奇怪的早晨 - 我收到以下错误（因为这个脚本是一个用于用虚拟数据填充表格的脚本）：

Msg 547, Level 16, State 0, Line 7
The INSERT statement conflicted with the FOREIGN KEY constraint "FK_ATTR". The conflict occurred in database "PhonebookDuplication", table "dbo.Attributes_Dummy", column 'Id'.
The statement has been terminated.

正如问题所暗示的那样，该表中的行仍然被插入（好像它没有强制执行外键约束）

我还测试了手动插入数据 - 它不会抛出这个错误。

这是我的表格的布局和我执行的脚本。我需要知道发生了什么，以及为什么它会引发错误:) 我敢打赌它是我忽略的一些明显的东西。

表格布局

脚本：

use PhonebookDuplication;

DROP TABLE Numbers_Attributes_Bridge;
DROP TABLE Numbers_Dummy;
DROP TABLE Attributes_Dummy;


CREATE TABLE Numbers_Dummy
            (
             Id int IDENTITY(1,1) PRIMARY KEY,
             Number VARCHAR(20),
             AccountId INT,
             FirstName VARCHAR(20),
             LastName VARCHAR(20)
            );


CREATE TABLE Attributes_Dummy
            (Id int IDENTITY(1,1) PRIMARY KEY,
             AccountId INT,
             Attribute VARCHAR(100)
            );

CREATE TABLE Numbers_Attributes_Bridge
            ( 
              NumberId int,
              AttributeId int,
              AccountId int,
              Value Varchar(100)
              CONSTRAINT PK_NA PRIMARY KEY
              (
                  NumberId ASC,
                  AttributeId ASC
              )
              CONSTRAINT FK_Numbers FOREIGN KEY (NumberId) REFERENCES Numbers_Dummy(Id),
              CONSTRAINT FK_ATTR FOREIGN KEY (AttributeId) REFERENCES Attributes_Dummy(Id),
            );

DECLARE @COUNTER INT = 0;
SET NOCOUNT ON
WHILE (@COUNTER < 150) 
BEGIN
    INSERT INTO Numbers_Dummy VALUES ('082'+CONVERT(varchar(15),@Counter),2000046,'Eon','du Plessis')
    SET @COUNTER += 1;
END

SELECT COUNT(*) FROM Numbers_Dummy

SET @COUNTER = 0;
WHILE (@COUNTER < 5)
BEGIN
    INSERT INTO Attributes_Dummy VALUES (2000046,'Attribute'+CONVERT(varchar(15),@Counter))
    SET @COUNTER += 1;
END 

SELECT COUNT(*) FROM Attributes_Dummy

DECLARE @COUNTER2 INT = 0 ;
DECLARE @SUBCOUNTER INT = 0; 
WHILE (@COUNTER2 <= 150)
BEGIN
    WHILE (@SUBCOUNTER <= 5)
    BEGIN
        INSERT INTO Numbers_Attributes_Bridge VALUES (@COUNTER2,@SUBCOUNTER,2000046, 'ATTRIBUTE-' + CONVERT(VARCHAR(100),@SUBCOUNTER))
        SET @SUBCOUNTER =@SUBCOUNTER + 1;
    END
    SET @SUBCOUNTER = 0;
    SET @COUNTER2 = @COUNTER2 + 1;
END

逻辑说 numbers_dummy 表将有 150 行，ID = 1 到 150 属性将有 5 行，ID = 1 - 5 Numbers_Attributes_Bridge 应该有 750 行： NumberID = 1 到 150，复合主键值为 AttributeID = 1 到 5

我收到上述错误，但行仍然插入。

以下代码行在手动测试中未引发错误：

INSERT INTO Numbers_Attributes_Bridge VALUES (150,5,2000046, 'ATTRIBUTE-5')

到底是怎么回事？

4

1 回答 1

1

哟搞砸了计数器，请尝试以下脚本：

DECLARE @COUNTER INT = 1;
SET NOCOUNT ON
WHILE (@COUNTER <= 150) 
BEGIN
    INSERT INTO Numbers_Dummy VALUES ('082'+CONVERT(varchar(15),@Counter),2000046,'Eon','du Plessis')
    SET @COUNTER += 1;
END

SELECT COUNT(*) FROM Numbers_Dummy

SET @COUNTER = 1;
WHILE (@COUNTER <= 5)
BEGIN
    INSERT INTO Attributes_Dummy VALUES (2000046,'Attribute'+CONVERT(varchar(15),@Counter))
    SET @COUNTER += 1;
END 

SELECT COUNT(*) FROM Attributes_Dummy

DECLARE @COUNTER2 INT = 1 ;
DECLARE @SUBCOUNTER INT = 1; 
WHILE (@COUNTER2 <= 150)
BEGIN
    WHILE (@SUBCOUNTER <= 5)
    BEGIN
        INSERT INTO Numbers_Attributes_Bridge VALUES (@COUNTER2,@SUBCOUNTER,2000046, 'ATTRIBUTE-' + CONVERT(VARCHAR(100),@SUBCOUNTER))
        SET @SUBCOUNTER =@SUBCOUNTER + 1;
    END
    SET @SUBCOUNTER = 1;
    SET @COUNTER2 = @COUNTER2 + 1;
END

尝试插入 NumberId 或 AttributeId = 0 的行时出现错误，但所有其他行都插入得很好，这就是插入一些记录的原因

于 2013-03-19T08:41:05.273 回答