我有一些表格如下：
Grandfather(id_grandfather, nameGrandfather,birthdate)
Father(id_father, nameFather, id_grandfather, birthdate)
Son(id_son, nameSon, id_father, birthdate)
我想选择所有数据儿子，父亲和祖父，如下图所示：
Son1 Father 1 grandfather1
Son2 Father 1 grandfather1
Son3 Father 2 grandfather1
Son4 Father 3 grandfather2
Son5 Father 4 grandfather2
因此创建了模型（mfamily.php），如下所示：
Class Mfamily extends CI_Model{
function joinFamily(){
$this->db->select('Son.id_son, Son.nameSon, Son.id_father, Father.id_father, Father.nameFather,Father.id_grandfather,Grandfather.id_grandfather,Grandfather.nameGrandFather');
$this->db->from('Son', 'Father', 'Grandfather');
$this->db->join('Grandfather', 'GrandFather.id_country = province.id_country');
$this->db->join('province','province.id_country = city.id_city');
return $this->db->get();
}
}
在控制器 cfamily.php
Class Cfamily extends CI_Controller{
$this->load->model(‘Mfamily’);
$data[‘family’]=$this->Mfamily-> joinFamily();
$this->load->view(‘vFamily’,$data);
}
我的观点 vFamily.php
<html>
<body>
</tr>
<?php if($family){ ?><?php
foreach ($family as $row) { ?>
<tr>
<td><?php echo $row->Son.nameSon?></td>
<td><?php echo $row->Father.nameFather?></td>
<td><?php echo $row->Grandfather.nameGrandfather?></td>
</tr>
<?php }?>
<?php }else{ ?>
<tr>
<td colspan="3" align="center">Empty</td>
</tr>
<?php } ?>
</body>
</html>
当我编译这个源代码时，我收到如下消息错误：
Error Number: 1054 Unknown column 'Father.id_grandfather' in 'on clause'
Filename: C:\xampp\htdocs\family\system\database\DB_driver.php
Line Number: 330
我的代码发生了什么？