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我正在尝试运行以下程序。但是，NullPointerException出现了一个。到目前为止，我已经在每一步都调试了我的代码。似乎在我实现numA.add()in main 之后出现了空指针异常。

主.java

public class Main {

    public static void main(String[]args){

        NumberSystem numA = new NumberSystem(new Number(20),new Number(10));
        numA.add();
        System.out.println(numA.getResult().toString());
    }
}

NumberSystem.java

public class NumberSystem {

    private Number n1,n2,result;

    public NumberSystem(){
        n1 = new Number(0);
        n2 = new Number(0);
        result = new Number(0);
    }

    public NumberSystem(Number n1,Number n2){       
        n1 = new Number();
        n2 = new Number();
        result = new Number(0);
    }   

    public NumberSystem(NumberSystem n){
        n1 = new Number(n.n1);
        n2 = new Number(n.n2);
        result = new Number(n.result);
    }

    public Number getN1(){
        return n1 = new Number(n1.getNum());
    }

    public Number getN2(){
        return n2 = new Number(n2.getNum());
    }

    public Number getResult(){
        return result = new Number(result.getNum());
    }

    public void setN1(int n1Value){
        if (n1Value != 0) n1 = new Number(n1Value);
    }

    public void setN2(int n2Value){
        if (n2Value != 0) n2 = new Number(n2Value);
    }

    public void add(){
        result = new Number(n1.getNum() + n2.getNum());
    }

    public String toString(){
        return "" + n1.getNum();
    }

}

数字.java

public class Number {

    private int num;

    public Number() {num = 0;}
    public Number(int numValue){
        if (numValue != 0) num = numValue;
    }

    public Number(Number anotherNum){
        num = anotherNum.getNum();
    }

    public int getNum(){
        return num;
    }

    public void setNum(int numValue){
        if (numValue != 0) num = numValue;
    }   

    public String toString(){
        return new String("" + num);
    }

}
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1 回答 1

3

你需要在你的构造函数中为类成员变量赋值NumberSystem。目前，您仅将这些值分配给传入的具有相同名称的本地值。

public NumberSystem(Number n1,Number n2){       
    n1 = new Number();  // Number assigned to local variable n1
    n2 = new Number();  // ditto for n2
    ...

然后，这会导致NPE您尝试在此行上分配结果：

result = new Number(n1.getNum() + n2.getNum());

相反，您可以使用：

this.n1 = new Number();
this.n2 = new Number();

或使用传入的值（！？）：

this.n1 = n1;
this.n2 = n2;
于 2013-03-18T23:30:26.817 回答